How Do You Calculate Voltmeter Readings Across Multiple Points?

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Homework Help Overview

The discussion revolves around calculating voltmeter readings across multiple points in a circuit, specifically focusing on the potential differences between points A, B, and C. The context involves understanding voltage measurements in relation to resistors in a circuit.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore how to find the potential difference between various points and question the method of subtraction for voltages. There are inquiries about the representation of circuit elements and the implications of using a voltmeter.

Discussion Status

Participants are actively engaging with each other's ideas, with some providing guidance on how to approach the problem of calculating voltage differences. There is a mix of interpretations regarding the setup and calculations, and while some steps are suggested, there is no explicit consensus on a single method.

Contextual Notes

There is mention of identical resistors in the circuit, which may simplify calculations, and participants are considering the implications of using Ohm's law in their reasoning. The discussion also reflects uncertainty about the values of the resistors and how they affect current distribution.

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See attachment.

The questions I have are finding the potential difference between A and B, between B and C, and finding the reading on a voltmeter placed between A and C.

I think that:

the potential difference between A and B is 8V.

between B and C is 4V

However, I was having trouble finding the reading on a voltmeter placed between A and C. Please can someone explain to me how to arrive at the correct answer.


Thank you.
 

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What do those rectangles represent?

If you know the voltage of A with respect to B and of C with respect to B, just subtract to find the voltage between A and C.
 
Last edited:
The rectangles are resistors. Which do I subract from the other?

Thanks
 
nokia8650 said:
Which do I subract from the other?
Doesn't matter. All you need is the magnitude of the voltage difference between them.
 
Thanks, is there any sort of formula/rule which I can use, rather than blindly subracting one from the other?

Thanks
 
All you are doing is finding the voltage difference between two points. Since you know the voltage of each with respect to a common reference (point B), all you need to do is compare them to see the difference (which is found by subtraction).
 
The rectangles are probably resistors.
What are their values?

You have probably done all this already to get to the potential difference AB and BC, but just in case:

The steps you need to take to answer your question:

1. Determine the effective resistance.
2. Determine the total current (through the source) using Ohm's law.
3. Determine the current through each branch using Ohm's law (remember that a current gets split up in parallel branches, while potential does not. Potential 'splits up' between resistors.)
4. Now you know the current through each branch (which will be the same for every resistor on that branch) you can use Ohm's law (yes, again) to calculate the voltage-loss over each resistor and thus you can calculate the potential difference on each point (A, B and C).

The potential difference between A and C V_{AC} is just V_A - V_C.EDIT
Maybe you were put off by the fact that the question is asked differently.
A voltage meter is simply a device that reads the voltage difference between the two points it's connected on.
An ideal voltage meter (which you are most probably using) has an infinite input resistance which means no current is going to flow into the meter, so the network has not been changed by adding the voltage meter.
 
Last edited:
Thanks a lot for all the help. The resistors are meant to be identical, and so its not quite as complicated as you explained, however that was very useful help for the future. Had the resistances been not equal, how would I carry out step 3 - determining how much current was through each branch?

Thanks
 
Assuming you know the total current (through the source) (let's call it I) then using Ohm's law you can calculate the current through each branch.

Let R_L be the effective resistance of the left branch and R_R the effective resistance of the right branch.
Then, I_L (current through left branch) is equal to \frac{12}{R_L} and I_R = \frac{12}{R_R}.

This is just Ohm's law: V = IR or I = \frac{V}{R}
 
Last edited:
  • #10
ahh yes, thanks, its so obvious! I really appreciate the help!
 

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