According to the text, at a distance of 50 m from a jet engine, the sound intensity is 10 W/m2. This corresponds to a loudness (or an intensity level) of 130 dB. [You should convince yourself that this is true.] If you find the sound too loud and you want to reduce the intensity by a factor of 10, to what new distance (approximately) from the jet engine should you move to achieve this reduction? I=P/Area Intensity level = 10db*log(I/Io) to find the power of the jet engine: p=10*((50^2)*4pi) =314159 a factor of 10 reduction would mean 13dB 13=10log(I/10^-12) 1.3=log(I)-log(10^-12) -10.7=log(I) I=10^-10.7 A=P/I A= 314159/ 10^-10.7 A=1.57x10^16 1.57x10^16 = 4pi r^2 r=397289 so does that mean that you really can't make the intensity decrease by a factor of 10?