Simple summation, difficult inference. (game theory)

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SUMMARY

The discussion centers on the substitution of variables within summation signs in the context of game theory, specifically regarding the zero payoff of skew symmetric games like rock-paper-scissors. The user seeks clarification on how to interpret the limits of summation, particularly how the sum from 1 to n can be equivalent to a sum from i to n. The explanation provided involves manipulating double summations and understanding the dependencies of variables, leading to a clearer comprehension of the proof.

PREREQUISITES
  • Understanding of basic game theory concepts, particularly skew symmetric games.
  • Familiarity with summation notation and its properties.
  • Knowledge of variable substitution in mathematical proofs.
  • Basic proficiency in mathematical manipulation of series and sequences.
NEXT STEPS
  • Study the properties of skew symmetric games in game theory.
  • Learn about double summations and their applications in mathematical proofs.
  • Explore variable substitution techniques in summation contexts.
  • Review examples of mathematical proofs involving summation limits and dependencies.
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Mathematicians, game theorists, students studying advanced mathematics, and anyone interested in understanding the intricacies of summation in proofs.

citrusvanilla
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hi guys, new user, long time lurker.

the following simple proof is proposed with the highlighted summations. you do not need to know what the proof is of to answer my question (it is that the payoff for a skew symmetric game, rock paper scissors, is zero). i need help understanding how you can substitute variables in summation signs. specifically, how the sum of the term in row 1 from 1 to n is somehow equivalent to the sum in row 2 from i to n. this doesn't make any sense to me. how can something be summed from i to n?

fyi assume x_i = y_i for all i

http://i.imgur.com/s9cdo.jpg

http://i.imgur.com/s9cdo.jpg
 
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The limits of the inside sigma can depend upon the variable of the outside.
Like if we have
1+(1+1)+(1+1+1)
we could write
[tex]\Sigma_{i=1}^3\Sigma_{j=i}^3 1[/tex]

if we have
x3+(x2+x3)+(x1+x2+x3)
we could write
[tex]\Sigma_{i=1}^3\Sigma_{j=i}^3 x^j[/tex]

to manipulate such we can focus on the possible value of each variable
if 0<i,j<n
if we prefer to work with i+j and i instead of j and i we have
0<i<n
i<i+j<n+i
 
thanks lurf i really appreciate it. after staring at your answer for 10 minutes i understood it, this is compared to the 3 hours i took to not understand the proof.
 

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