Simple Train Acceleration after elapsed time question

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SUMMARY

The discussion centers on calculating the speed of a train after a specified time under constant acceleration. The train reaches a speed of 4.6 m/s in 5.2 seconds. To find the speed after an additional 6.0 seconds, users are advised to first determine the acceleration using the formula v = v_0 + at, where v_0 is the initial speed and a is the acceleration. The importance of calculating acceleration before determining the final speed is emphasized, ensuring accurate results in similar physics problems.

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  • Understanding of basic kinematics
  • Familiarity with the formula v = v_0 + at
  • Knowledge of constant acceleration concepts
  • Ability to perform unit conversions if necessary
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As a train accelerates away from a station, it reaches a speed of 4.6 m/s in 5.2 s.

If the train's acceleration remains constant, what is its speed after an additional 6.0s has elapsed?

I know I should be able to do this,but nothing I try works.If anyone could just point me the right way, I would really appreciate it. Thank You.
 
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Well if you have the change in speed and change in time, then what is the acceleration? Then once you have that, you can plug that into:

v = v_0 + at
 
Thanks a lot, I really appreciate the help. I was going insane, but I realize I skipped the fact that I needed to find the acceleration first.

I won't make that mistake again. Once again thanks for the help!
 

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