# Simple Train Acceleration after elapsed time question

1. Sep 1, 2008

### rsfancy

As a train accelerates away from a station, it reaches a speed of 4.6 m/s in 5.2 s.

If the train's acceleration remains constant, what is its speed after an additional 6.0s has elapsed?

I know I should be able to do this,but nothing I try works.If anyone could just point me the right way, I would really appreciate it. Thank You.

2. Sep 1, 2008

### chislam

Well if you have the change in speed and change in time, then what is the acceleration? Then once you have that, you can plug that into:

$$v = v_0 + at$$

3. Sep 1, 2008

### rsfancy

Thanks a lot, I really appreciate the help. I was going insane, but I realize I skipped the fact that I needed to find the acceleration first.

I wont make that mistake again. Once again thanks for the help!!