Simple trig which I have forgotten

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Homework Help Overview

The discussion revolves around a physics problem involving a small ball attached to a string, where the ball is displaced at an angle from the vertical. The objective is to determine the height of the ball at this angle, which is part of a larger question concerning potential energy calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the length of the string and its representation in different forms (0.33m vs. 1/3m). There are attempts to clarify the trigonometric relationships involved in calculating the height of the ball, with some participants questioning the meaning of the coordinates derived from trigonometric functions.

Discussion Status

Some participants have provided clarifications regarding the string length and the trigonometric calculations. There is ongoing exploration of how to apply these calculations to find the height, with no explicit consensus reached yet.

Contextual Notes

Participants are working within the constraints of basic trigonometry and potential energy concepts, with some expressing uncertainty about their understanding of the trigonometric functions involved.

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Homework Statement


Small ball fastened to a piece of string 0.33m in length. The ball is displaced by 60 degrees from the vertical. What is the height of the ball at this point?

Homework Equations


sin? cos? tan?

The Attempt at a Solution


This is part of a bigger physics question in which I need to work out potential energy (mass*9.8*height). I have forgotten my basic trigonometry :blushing: and need help finding out the height.
 
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NOP90 said:

Homework Statement


Small ball fastened to a piece of string 0.33m in length. The ball is displaced by 60 degrees from the vertical. What is the height of the ball at this point?


Homework Equations


sin? cos? tan?


The Attempt at a Solution


This is part of a bigger physics question in which I need to work out potential energy (mass*9.8*height). I have forgotten my basic trigonometry :blushing: and need help finding out the height.

Is the string 1/3 m or .33m? If it's given as 1/3 m. don't use such a crude approximation as .33m. If it's given as .33 m, then you're OK.

An equivalent problem is this: Pull the ball to the right so that the string is horizontal. Swing the ball down by 30 degrees. If the string's length is r meters, and the string is fastened at the origin (0, 0), the position of the ball will be (r cos(-30 deg.), r sin(-30 deg.)) = (r sqrt(3)/2, -r/2). All you have to do is figure out how high this point is above the low point when the ball is hanging straight down.
 
Mark44 said:
Is the string 1/3 m or .33m? If it's given as 1/3 m. don't use such a crude approximation as .33m. If it's given as .33 m, then you're OK.

Sorry mate, it's 0.33m, originally 330mm but I am working in SI units.
 
Mark44 said:
(r cos(-30 deg.), r sin(-30 deg.)) = (r sqrt(3)/2, -r/2). All you have to do is figure out how high this point is above the low point when the ball is hanging straight down.

I'm a bit confused with that. So the length of string is 0.33m. Do I calculate 0.33*cos(-30deg.)? What does the comma between rcos(-30deg.) and rsin(-30deg) represent? Do I use both calculations? Do I also calculate what is on the right of the = ?
 
Yes, r = .33. The comma between rcos(-30deg.) and rsin(-30deg) is there because these are the x and y coordinates of a point.

Draw a picture...
 

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