Simple Uniform Acceleration Problem

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Homework Help Overview

The problem involves a bicycle accelerating from rest, covering a distance of 16 meters in 4 seconds, with a total mass of 90 kg. The objective is to determine the average acceleration during this time period.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss various equations related to motion, including average velocity and acceleration formulas. Some express confusion regarding the application of these equations and question the correctness of their calculations. There is a suggestion to use the equation for displacement under uniform acceleration.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the assumptions about acceleration being constant. Some guidance has been offered regarding the use of specific equations, but no consensus has been reached on the correct approach.

Contextual Notes

There is a noted confusion regarding the distinction between average acceleration and instantaneous acceleration, as well as the implications of the problem's wording. Participants are also addressing the potential errors in the equations used for calculations.

TheKovac
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Homework Statement


A bicycles accelerates from rest, covering 16 metres in 4 seconds. The total mass of the bicycle and its rider it 90kg. What is its average acceleration during this time?

Homework Equations


x = ut + 0.5at^2
v=xt
a=vt

The Attempt at a Solution


v = x/t
v = (16)/(4)
v = 4 m/s

F = mv/t
F = (90)(4)/4
Fnet = 90N

Fnet = ma
90 = 90a
A= 1 m/s^2 <--WRONG! - How?
A=2ms <--- RIGHT
 
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TheKovac said:

Homework Statement


A bicycles accelerates from rest, covering 16 metres in 4 seconds. The total mass of the bicycle and its rider it 90kg. What is its average acceleration during this time?

Homework Equations


x = ut + 0.5at^2
v=xt
a=vt

The Attempt at a Solution


v = x/t
v = (16)/(4)
v = 4 m/s

F = mv/t
F = (90)(4)/4
Fnet = 90N

Fnet = ma
90 = 90a
A= 1 m/s^2 <--WRONG! - How?
A=2ms <--- RIGHT

Why didn't you just use x = ut + 0.5at^2 ?
 
TheKovac said:

Homework Statement


A bicycles accelerates from rest, covering 16 metres in 4 seconds. The total mass of the bicycle and its rider it 90kg. What is its average acceleration during this time?

Homework Equations


x = ut + 0.5at^2
v=xt
a=vt

Your equations are not quite right here and they are leading to some problems. The second and third equations need to be:

<br /> v_{\rm average} = \frac{x_f-x_i}{\Delta t}<br />

<br /> a_{\rm average} = \frac{v_f-v_i}{\Delta t}<br />

The Attempt at a Solution


v = x/t
v = (16)/(4)
v = 4 m/s

This quantity you have calculated is the average velocity over the whole time period.

F = mv/t
F = (90)(4)/4
Fnet = 90N

Dividing the average velocity by the time here does not give you the average acceleration; you would need the beginning and ending velocities.


However, if you use your first equation:

<br /> \Delta x = v_0 t + \frac{1}{2} a t^2<br />

you should get the right answer immediately.
 
You can't use a constant acceleration law - The question never said that the acceleration was constant, it wanted you to find the average acceleration.
Also:
average velocity = displacement / time interval
average acceleration = change in velocity / time interval

16/4 = average velocity
 

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