- #1

WRS

- 3

- 0

- Homework Statement
- Yes

- Relevant Equations
- Pythagoras, Trigonometry

Hi there,

I have attached the problem I'm working with.

I believe I must have the wrong idea of how to approach this question.

My issue is with the stated width and calculating how long the boat will take to cross the river.

It's using width; 110m and the boats velocity to determine how long the boat will take to cross the river. Later in the section it states that the boat will have drifted 71m downstream.

My assumption is that if the river was 110m (shore to shore) and the boat drifted 71m down stream the actual distance traveled by the boat would be found using c^2 = a^2 + b^2

Distance traveled =

Distance traveled = 130.9m (1.dp)

And therefore the time taken to travel would be founding using width 130.9m, rather than 110m?

Thank you very much

I have attached the problem I'm working with.

I believe I must have the wrong idea of how to approach this question.

My issue is with the stated width and calculating how long the boat will take to cross the river.

It's using width; 110m and the boats velocity to determine how long the boat will take to cross the river. Later in the section it states that the boat will have drifted 71m downstream.

My assumption is that if the river was 110m (shore to shore) and the boat drifted 71m down stream the actual distance traveled by the boat would be found using c^2 = a^2 + b^2

Distance traveled =

**√**110^2 + 71^2Distance traveled = 130.9m (1.dp)

And therefore the time taken to travel would be founding using width 130.9m, rather than 110m?

Thank you very much