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HelpMeWIN123
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Simple velocity vector problem; IS MY SOLUTION MANUAL WRONG OR AM I?!
A particle starts from the origin with velocity 5i at t=0, and moves in the xy plane with a varying acceleration given by a= 6 Sqrt(t) j, where t is in s.
a.) Determine the vector velocity of the particle as a function of time.
Vi=5i; a = 6 sqrt(t)j
Vf=Vi+at
Vf = Vfx +Vfy = (Vix+axt)i+(Viy+ayt)j
=(5+0)i + (0+6sqrt(t)*t)j
=5i +6t^3/2 j
The solution manual states the answer as Vf=5i +4t^3/2 j
Whos right here?
Homework Statement
A particle starts from the origin with velocity 5i at t=0, and moves in the xy plane with a varying acceleration given by a= 6 Sqrt(t) j, where t is in s.
a.) Determine the vector velocity of the particle as a function of time.
Homework Equations
Vi=5i; a = 6 sqrt(t)j
Vf=Vi+at
Vf = Vfx +Vfy = (Vix+axt)i+(Viy+ayt)j
=(5+0)i + (0+6sqrt(t)*t)j
=5i +6t^3/2 j
The solution manual states the answer as Vf=5i +4t^3/2 j
Whos right here?