1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simplify each expression: 2/1+y-2 /2x^3+x

  1. Aug 28, 2011 #1
    1. The problem statement, all variables and given/known data

    2/1+y-2 /2x^3+x its all over top of 2x^3+x

    2. Relevant equations



    3. The attempt at a solution

    should i multiply the top by 1+y, like the 2 and the -2.
     
  2. jcsd
  3. Aug 28, 2011 #2
    can you use parentheses to make this clearer?
     
  4. Aug 28, 2011 #3
    Picture0006.jpg heres a picture of it its d)
     
    Last edited: Aug 28, 2011
  5. Aug 28, 2011 #4
    you have [tex] \frac{\frac{2}{1+y}-2}{2x^3+x} [/tex]

    next you should do [tex] \frac{\frac{2}{1+y}-\frac{2(1+y)}{(1+y)}}{2x^3+x} [/tex]
     
  6. Aug 28, 2011 #5
    so would this be the final answer. -2y/2x^3+x
     
  7. Aug 28, 2011 #6
    I think you copied the problem wrong! And no that would not be the answer, you dropped a (1+y) somewhere.
     
  8. Aug 28, 2011 #7
    sorry im feeling a little stressed i got to 2y/1+y/2x^3+x I've forgotten how to do everything lol.
     
  9. Aug 28, 2011 #8
    For problem d, [tex] \frac{\frac{2}{1+y}-2}{y} [/tex]
    Start the same way as before with [tex] \frac{\frac{2}{1+y}-\frac{2(1+y)}{(1+y)}}{y} [/tex]

    which becomes [tex] \frac{\frac{2y}{1+y}}{y} [/tex]

    then remember the denominator "y" is actually [tex] \frac{y}{1} [/tex]
    so you have [tex] \frac{\frac{2y}{1+y}}{\frac{y}{1}} [/tex]

    and to divide to fractions you multiply by the reciprocal like this: [tex] \frac{2y}{(1+y)}(\frac{1}{y}) [/tex]

    then just cancel a y from the top and bottom and you're done
     
  10. Aug 28, 2011 #9
    god I wrote it down wrong thanks.
     
  11. Aug 28, 2011 #10
    so that would make it 2/y^2
     
  12. Aug 28, 2011 #11
    eek! no.
    its [tex] \frac{2y}{y(1+y)} [/tex]

    which gives [tex] \frac{2}{1+y} [/tex]
     
  13. Aug 28, 2011 #12

    Ray Vickson

    User Avatar
    Science Advisor
    Homework Helper

    No: you have written [tex]\frac{-2y}{2x^3} + x[/tex]. Did you mean to write
    [tex]\frac{-2y}{2x^3 + x}?[/tex] If so, then USE BRACKETS, like this: -2y/(2x^3+x). Isn't that simple? It makes everything clear and removes all confusion.

    RGV
     
  14. Aug 28, 2011 #13
    that was pointless...
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Simplify each expression: 2/1+y-2 /2x^3+x
  1. 7^2x+3 / 7^x^2 = 1 (Replies: 5)

  2. Y = x^2-a(x+1)+3 (Replies: 9)

Loading...