Simplify the expression assume all variables are positive?

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SUMMARY

The discussion focuses on simplifying three mathematical expressions involving cube roots and radicals. The first expression, \(\sqrt[3]{-8x^3y^3z^3}\), simplifies to \(-2xyz\). The second expression, \(\frac{4xy^{-1}}{16xy^2}\), reduces to \(\frac{1}{4y^3}\) after addressing the negative exponent and simplifying the fraction. The third expression, \(\sqrt{98}+\sqrt{2}\), can be expressed as \(7\sqrt{2}+\sqrt{2}\), which further simplifies to \(8\sqrt{2}\).

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chris4434
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I have three math problems that I am unsure of how to do. could someone please help thanks.

[tex]\sqrt[3]{-8x^3y^3z^3}[/tex]

[tex]({4xy^-1}/{16xy^2})[/tex]

[tex]\sqrt{98}+\sqrt{2}[/tex]
 
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chris4434 said:
I have three math problems that I am unsure of how to do. could someone please help thanks.

[tex]\sqrt[3]{-8x^3y^3z^3}[/tex]

[tex]({4xy^-1}/{16xy^2})[/tex]

[tex]\sqrt{98}+\sqrt{2}[/tex]

Well for the first one you have the cube roots of 3 numbers which have been cubed so what do you think you should do?

For the second I'm not entirely sure what the expression is supposed to be but the only thing I can think of is to expres it without the negative exponent.

For the third the two radicals need to be in terms of a common radical so see if you can figure out to make [tex]\sqrt{98}[/tex] into some number times the square root of 2.
 
chris4434 said:
I have three math problems that I am unsure of how to do. could someone please help thanks.

[tex]\sqrt[3]{-8x^3y^3z^3}[/tex]
What is [itex]\sqrt[3]{-8}[/itex]?
What is [itex]\sqrt[3]{x^3}[/itex]?


[tex]({4xy^{-1}}/{16xy^2})[/tex]
What is [itex]\frac{4}{16}[/itex]?
You have an "x" in both numerator and denominator. What can you do with that?
What does a -1 power mean?

[tex]\sqrt{98}+\sqrt{2}[/tex]
98= 2(?)
 

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