Simplify this equation and express it as a radical

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The discussion focuses on simplifying the expression (16x7/y4)1/3 and expressing it as a radical. Participants suggest breaking down the expression into factors, specifically looking for perfect cubes. The final simplified form is ((2x)4/y)1/3 * (x/y). Key insights include the importance of identifying perfect cubes and factoring appropriately to achieve the desired radical expression.

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justinepearle
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I have to simplify this equation and express it as a radical at the end.
16x^7 / y^4 and cube root everything.




I've tried expressing everything as exponents but it doesn't seem to get me to where i want to go. I attempted at factoring into two radicals with one containing a perfect square, but i didn't quite know how to do it and got nothing close to something that looked right.

Any help?
 
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(\frac{16x^7}{y^4})^\frac{1}{3}

(\frac{16x^4}{y}*\frac{x^3}{y^3})^\frac{1}{3}

that should get you started
 
justinepearle said:
I've tried expressing everything as exponents but it doesn't seem to get me to where i want to go. I attempted at factoring into two radicals with one containing a perfect square[/color], but i didn't quite know how to do it and got nothing close to something that looked right.

That's your problem right there[/color]! You should be looking for a perfect cube, right?
 
sorry, typo
 
OK, then show us what you've done. rock.freak started it for you, but there is still more work do to inside the parentheses.
 
I've got it down to
((2x)^4/Y)^(1/3) x (x/y)
 
Good. Now there's still a little more to do. Can you break (2x)^4 down into a perfect cube, and another factor that is not a perfect cube?
 
Once you take Tom Mattson's hint you should have everything under control. I'm just going to put in my oar to point out that this is an expression, not an equation.
 

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