Simplifying (2/6 -root3)^2 - (2/6+root3)^2

[binomialgurl]

im having trouble trying to figure out a problem. can someone help me.

(2/6 -root3)^2 - (2/6+root3)^2

if that makes sense to anyone help.

I think that the denominator of both has to be rationalised but do i expand the squared brackets first or later or what?

any ideas welcome thanks

 

[tramtran111]

I think you can use the difference of 2 squares a^2 - b^2 = ( a+b) (a-b). good luck!

 

[Tedjn]

Do you mean

\left(\frac{2}{6-\sqrt{3}}\right)^2 - \left(\frac{2}{6+\sqrt{3}}\right)^2

What are you supposed to do with this? Simplify?

 

[PuzzledMe]

Don't expand first. Use a^2 - b^2 = (a+b) (a-b) as tram said, at denominator, remember to do two times due to the square. This is to make denominator a whole number. Account for the multiplication for the numerator too.

 

[binomialgurl]

I am supposed to evaluate it.
And thanks for all the advice by the way.