Simplifying a solution that has complex eigenvalues

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SUMMARY

The discussion focuses on simplifying solutions to differential equations with complex eigenvalues, specifically using the example x'=[-1/2 1; -1 -1/2]x. The characteristic equation yields eigenvalues r = -1/2 ± i. The solution can be expressed as x = e^{-t/2}(C1(cos(t) + i sin(t))(1 i)T + C2(cos(-t) + i sin(-t))(1 -i)T). The simplification process involves recognizing that sin(-t) = sin(t) and cos(-t) = -cos(t), leading to the final form C1e^{-t/2}(cos(t) - sin(t))T + C2e^{-t/2}(sin(t) cos(t))T, as stated in the textbook.

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  • Understanding of linear differential equations
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  • Knowledge of Euler's formula
  • Basic skills in complex number manipulation
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Students and educators in mathematics, particularly those studying differential equations, linear algebra, and complex analysis. This discussion is beneficial for anyone seeking to deepen their understanding of eigenvalue problems and their solutions.

Jamin2112
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Homework Statement



I'll give an example.

Ex: x'=[-1/2 1; -1 -1/2]x.

Homework Equations



Assume a solution of the form x=$ert for these type of problems.

Euler's formula: ebi = cosb + isinb

The Attempt at a Solution



|A-rI|=0

---> r= -1/2 +/- i

---> x= e-t/2 ( C1(cost + isint)(1 i)T + C2(cos(-t) +isin(-t))(1 -i)T )

I understand that I can simplify a little with the fact that sin(-t)=sin(t) and cos(-t)=-cos(t), but I don't understand how to simplify it all the way to

C1e-t/2 (cost -sint)T + C2e-t/2(sint cost)T,

which is the answer in the book.

So, explain.
 
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so basically your 2 linearly independent solutions are

[tex]\textbf{x}_1 = e^{-t/2}(cos(t) + i.sin(t))(\begin{matrix} 1 \\ i \end{matrix})[/tex]
[tex]\textbf{x}_2 = e^{-t/2} (cos(-t) + i.sin(-t))(\begin{matrix} 1 \\ -i \end{matrix})[/tex]

note that any linear combination of these will also be a solution, so perhaps you could try taking 2 linear combinations that simplify things... making sure they are still linearly independent
 

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