Simplifying Algebra: Grade 11 Maths Q

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Homework Help Overview

The discussion revolves around simplifying the algebraic expression (4 - 1/x) / (4 + 1/x), which is part of a grade 11 mathematics problem focused on thinking and problem-solving skills.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore various methods for simplification, including clearing fractions and using reciprocals. Some express uncertainty about the process of clearing fractions, while others suggest multiplying by the denominator to simplify the expression.

Discussion Status

The conversation includes attempts to clarify the simplification process, with some participants providing hints and guidance without offering direct solutions. There is an ongoing exploration of different approaches, and participants are questioning the effectiveness of their methods.

Contextual Notes

Some participants mention a lack of formal instruction on specific techniques, such as clearing fractions, which may affect their understanding and approach to the problem.

jamie_23
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I am in grade 11 mathematics...i got this as a Thinking & Problem Solving Q..can someone simplify this, step by step?


4 - 1/x
---------
4 + 1/x


THANKS!
 
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You need to show us some of your work or thoughts on the problem.

Here's a hint. Clear the fractions first.
 
ok..the way i thought was taking the negative reciprocal of the denominator..
making it (4-1/x)(4-1/x)
---------------
(4+1/x)(4-1/x)
=16-8 1/x+1/x^2
----------------
16-1/x^2

does that work?
I haven't been taught how the clear the fractions.
 
I haven't been taught how the clear the fractions.

Sure you have... Just think about it for a bit. What would you multiply top and bottom by?
 
jamie_23 said:
ok..the way i thought was taking the negative reciprocal of the denominator..
making it (4-1/x)(4-1/x)
---------------
(4+1/x)(4-1/x)
=16-8 1/x+1/x^2
----------------
16-1/x^2

does that work?
I haven't been taught how the clear the fractions.
Simplifying should never change the outcome of an equation. You can therefore check if your simplification is correct by letting x equal any number. The original and simplified equations will produce the same answer if the simplification is correct.

So, let x=2
Your first equation gives (4 - 1/2) / (4 + 1/2) = .77778
Your simplified equation gives (16 - 8/2 + 1/4) / (16 - 1/4) = .77778

So your simplification is correct however it is probably not a "simplification". It looks more complex. What Integral is saying is that you can get rid of a fraction by multiplying it (and all other parts of the equaion by the denomonator of the fraction. This is particularly usefull if you have the same problem in multiple parts fo the equation.

For example, (1 + 1/x) / (2 + 3/x) can be simplified by multiplying both the top and bottom lines by x (the denomonator of the fraction).

You then get (x + 1) / (2x + 3) - much simpler form than the original.
You can then multiply by the reciprical if you wish (gives you (-2x^2 + x + 3) / (-4x^2 + 9) ) but it is not as simple is it?

For the same reason as multiplying by the reciprical, multiplying both parts by the denomonator does not change the outcome of the equation because x/x = 1
 
jamie_23 said:
I am in grade 11 mathematics...i got this as a Thinking & Problem Solving Q..can someone simplify this, step by step?


4 - 1/x
---------
4 + 1/x


THANKS!

If I understand this correctly, (4-1/x)/(4+1/x)

I'm not going to asnwer the question for you. But let's look at something simplier. (1/2)/(1/8) to make things simple multiply the two together like this (1/2) * (8/1) = (8/2) or 4. Just flip the bottom term upside (take the reciprocal) & multiply. Hope that helps.
 
first, (4-1/x)/(4+1/x) common denominators maybe?
(4/x-1/x)/(4/x+1x)
than
[(4x-1)/x]/[(4x+1/x)]
Multiply by the recpricoal of the denominator now... Can you see?

You should see that some things will cancel.
 

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