Simplifying Boolean Expression with Boolean Algebra

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SUMMARY

The discussion focuses on simplifying the Boolean expression f(x,y,z)=(x+y+z')(x+y'+z')(x'+y'+z) using Boolean algebra techniques. Participants suggest multiplying out the expression and applying simplification rules such as distribution and the identity aa' = 0. The emphasis is on using the distributive property to break down the expression systematically for simplification.

PREREQUISITES
  • Understanding of Boolean algebra concepts
  • Familiarity with Boolean expressions and their components
  • Knowledge of simplification rules such as distribution and identity laws
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Study the distributive property in Boolean algebra
  • Learn about the identity and null laws in Boolean expressions
  • Practice simplifying complex Boolean expressions
  • Explore tools for Boolean expression simplification, such as Karnaugh maps
USEFUL FOR

This discussion is beneficial for students studying digital logic design, electrical engineers, and anyone interested in mastering Boolean algebra for circuit design and optimization.

ece1111
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can anyone help me simplify this expression..
f(x,y,z)=(x+y+z')(x+y'+z')(x'+y'+z)..
:confused:
 
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OK, not sure whether this is homework or not, so I can't give you an answer, (even if mine's right at the moment), so I suggest you "multiply it out" and simplify what can and see if we get the same answer.
 
use this rule (a + b)c = ac + bc repeatedly.
you also have aa'= 0

hope this helps
 

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