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Boolean algebra prrof question

  1. Oct 6, 2013 #1
    1. The problem statement, all variables and given/known data

    Prove the following expression using Boolean algebra:

    1. X'Y' + Y'Z + XZ + XY + Z'Y = X'Y' + XZ + YZ'

    2. Relevant equations

    Laws of Boolean algebra

    3. The attempt at a solution

    I tried to take Y common but failed. I did the same with X and Z, but the method did not work. Any hints, please?
     
  2. jcsd
  3. Oct 6, 2013 #2

    haruspex

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    The two sides are the same except for two extra terms on the left, XY and Y'Z. So you need to show that those two are subsumed by the others. E.g. For Y'Z, you can break it up as Y'ZX+Y'ZX'. Can you find other terms on the left which subsume those?
     
  4. Oct 6, 2013 #3
    Thanks, I got it.
     
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