Boolean algebra prrof question

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SUMMARY

The forum discussion centers on proving the Boolean algebra expression X'Y' + Y'Z + XZ + XY + Z'Y = X'Y' + XZ + YZ'. Participants emphasize the need to demonstrate that the terms XY and Y'Z are subsumed by the other terms. A suggested approach involves breaking down Y'Z into Y'ZX + Y'ZX' to facilitate the proof. This method effectively simplifies the expression and confirms the equivalence of both sides.

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Homework Statement



Prove the following expression using Boolean algebra:

1. X'Y' + Y'Z + XZ + XY + Z'Y = X'Y' + XZ + YZ'

Homework Equations



Laws of Boolean algebra

The Attempt at a Solution



I tried to take Y common but failed. I did the same with X and Z, but the method did not work. Any hints, please?
 
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The two sides are the same except for two extra terms on the left, XY and Y'Z. So you need to show that those two are subsumed by the others. E.g. For Y'Z, you can break it up as Y'ZX+Y'ZX'. Can you find other terms on the left which subsume those?
 
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Thanks, I got it.
 

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