ciubba
- 65
- 2
I need to find the local extrema of
[tex]\pi r^2(\frac{16}{(r+.5)^2}-1)[/tex]
which I derived and simplified to
[tex]\frac{16 \pi r}{(r+.5)^3}=2 \pi r[/tex]
which simplifies to [tex]\frac {16 \pi r}{2 \pi r}=(r+.5)^3[/tex]
The radius cannot be zero, so I simplified [tex]8=(r+.5)^3[/tex]
I used the binomial theorem and more algebra to obtain
[tex]r^3+1.5r^2+.75r-7.875[/tex]
Now I am unsure of how to simplify the cubic. Normally I would use rational roots, but I don't know how to do that with an integer constant. I need either a method of simplifying this cubic or a place where I could have simplified the derivative better.
[tex]\pi r^2(\frac{16}{(r+.5)^2}-1)[/tex]
which I derived and simplified to
[tex]\frac{16 \pi r}{(r+.5)^3}=2 \pi r[/tex]
which simplifies to [tex]\frac {16 \pi r}{2 \pi r}=(r+.5)^3[/tex]
The radius cannot be zero, so I simplified [tex]8=(r+.5)^3[/tex]
I used the binomial theorem and more algebra to obtain
[tex]r^3+1.5r^2+.75r-7.875[/tex]
Now I am unsure of how to simplify the cubic. Normally I would use rational roots, but I don't know how to do that with an integer constant. I need either a method of simplifying this cubic or a place where I could have simplified the derivative better.