Simplifying f=uRuR in D3: A Beginner's Guide

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SUMMARY

The discussion focuses on simplifying the expression f = u R u R within the context of D3, the dihedral group representing the symmetries of an equilateral triangle. The key conclusion is that through the application of group relations, specifically u^2 = 1 and R^3 = 1, the expression simplifies to R = 1. Participants clarify that u and R are elements of the group, with u representing reflections and R representing rotations. The discussion emphasizes the importance of understanding group operations and relations to solve problems in dihedral groups.

PREREQUISITES
  • Understanding of dihedral groups, specifically D3
  • Familiarity with group theory concepts such as group operations and relations
  • Knowledge of the notation for rotations and reflections in groups
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties and relations of dihedral groups, focusing on Dn
  • Learn about group homomorphisms and isomorphisms in group theory
  • Explore examples of symmetry groups in geometry beyond D3
  • Practice simplifying expressions using group relations in other dihedral groups
USEFUL FOR

This discussion is beneficial for students and enthusiasts of abstract algebra, particularly those studying group theory, as well as educators seeking to explain dihedral groups and their applications in geometry.

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Homework Statement



In D3, simplify f = u R u R


Homework Equations






The Attempt at a Solution



u(Ru)R=(uR)uR
u(uR^2)R=(uR)u2
uR=R

I am doing this for independent study, and the website I am using says the solution is 1=R

I just got started on dihedral groups and have no idea what in the heck to do. How do you tell which is a rotation or reflection before the solution arises and/or arrive with the above answer of R=1

Thanks
 
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I have no idea what the notation "u R u R" means. Are u and R members of the group or something else?
 
I have no idea what the notation "u R u R" means. Are u and R members of the group or something else?

That is the way the problem is stated. Here are some relevant equations and an example problem.

Relevant equations:
To describe the group operation of Dn, we need only note the following rules (called "relations"):
u^2 = 1 (in fact, uk^2 = 1 for every reflection uk)
Rn = 1 (so R-1 = R^n-1)
R u = u R-1 = u R^n-1

To make calculations unambiguous, we agree that every element of Dn will have a standard form:

Rotations: Rk (or 1 for the identity = R0)
Reflections: u Rk (or just u itself if k = 0)
Since Rn = 1, we can take k between 1 and n-1

Example problem:
Example 1: In D3, the symmetry group of the equilateral triangle, calculate a = u R2 u.

Here is a sequence of steps using the relations in D3 along with associativity:
a = u R2 u = (u R2) u = u (R2 u)
= u (R R u) = u R (u R2)
(note we are using relation 3 above, for n = 3)
= u (R u) R2 = u u R4
(now use relations 1 and 2)
= u 2 R4 = R
So we conclude: a = u R2 u = R in D3
 

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