Simplifying the Buckingham equation

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Homework Help Overview

The discussion revolves around the Buckingham equation and the process of rearranging it to isolate V2. Participants are attempting to reconcile their own calculations with the answers provided in their textbooks.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are sharing their attempts at rearranging the Buckingham equation and expressing confusion over discrepancies between their results and textbook answers. Questions about the interpretation of terms and the correct application of mathematical operations are raised.

Discussion Status

Some participants have offered clarifications regarding the mathematical expressions involved, while others are reflecting on their misunderstandings. There is an acknowledgment of the complexity of the problem and a willingness to explore different interpretations.

Contextual Notes

Participants are working with an image of the equation and are referencing their lecture notes and textbooks. There is mention of previous attempts to seek help elsewhere without success.

stevemilw
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Hello, i have a question which is too hard for me to type in here, so I've scanned in the image.
At the top, as explained in the image, i have the answer I've found in my lecture notes, but then I've worked it out for myself and i do not get the same answer.
Can someone please tell me where I am going wrong?
Im making V2 the subject

All help is appretiated, don't be shy.
Thanks!

heres the link: http://www4.picturepush.com/photo/a/6324532/640/6324532.jpg

p.s i originally posted this in yahoo answers but got no response.
 
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hello stevemilw! :smile:

i don't understand what you mean by "the apparent answer leaves me with a negative square root and no divider" :confused:

(and your z1 + z2 should be 2g(z1 + z2))
 
Hello
What i meant by that is my answer (at the very bottom) gave me the top part with the pressures devided by the bottom part.
Also I am not sure what you meant by it should be 2G(Z1+Z2) because as i x2g on both sides, shouldn't i only times by one of the sides either side of the plus? writing this now, that seems stupid. You must be right.

What i mean by the whole thing, is you have the buckingham equation at the very top.
Second equation is the answer that my textbook says i should get when i re-arrange the formula to make V2 the subject.
The third equation annd the next and so on are my attempts. And i do not the the answer my textbook gives as you can see at the bottom.

Thanks
 
stevemilw said:
Second equation is the answer that my textbook says i should get when i re-arrange the formula to make V2 the subject.
The third equation annd the next and so on are my attempts. And i do not the the answer my textbook gives as you can see at the bottom.

they look the same to me :confused:

(with X-1/2 instead of 1/√X )
 
ooooh, i feel really stupid now.
I didnt realize that x^-1/2 was 1/sqrt x

God, you wouldn't believe the amount of hassel that's given me!

I know -1 was one over, to the negetive half is 1 over the sqrt.

Thanks, this is something I am not going to forget in a while! lol
 

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