Simultaneous Equations From Kirchhoff's Rules

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SUMMARY

The discussion focuses on solving for three unknown currents (I1, I2, I3) using Kirchhoff's Rules and simultaneous equations. The equations provided are I1 + I2 = I3, I1 = (-I3R3 - V2) / (R2), and I2 = (-I3R3 + V1) / (R1). The user has made progress by isolating I3 but requires assistance in rearranging the terms to solve for it definitively. The solution involves moving all terms with I3 to one side and factoring out the current.

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  • Understanding of Kirchhoff's Laws
  • Knowledge of simultaneous equations
  • Familiarity with algebraic manipulation
  • Basic circuit analysis concepts
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  • Practice solving simultaneous equations in circuit analysis
  • Learn how to apply Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL) in complex circuits
  • Explore techniques for isolating variables in algebraic equations
  • Study the implications of resistance (R1, R2, R3) and voltage (V1, V2) in circuit behavior
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Homework Statement


For a Lab report I have to solve for three unknown currents from Kirchoff's Rules equations using simultaneous equation algebra, and I'm completely stumped.

Homework Equations



From Loop and junction equations, the three equations that I have are

I1 + I2 = I3

I1= (-I3R3 - V2)/ (R2)

I2= (-I3R3+V1)/(R1)

The Attempt at a Solution



This is the farthest I have gotten, solving for I3. Once I have expression for this I will be able to plug back into the I1 and I2 equations fairly easy.

(-I3R3R2+ -I3R3R1+ -V2R1) / (R1R2)

= I3R1R2

Sorry If this is confusing. Thanks for any help in advance.
 
Last edited:
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You should just have to move all the terms with I3 to one side of the equation and factor out the current. That should give you an answer for I3.
 

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