(adsbygoogle = window.adsbygoogle || []).push({}); Sin [Pi. (x-1)] / x-1; for x =1,2,3,.....N

Sin [ Pi. (x-1) ] / (x-1) = ?

for x=1,2,3,4,......N

I think for Sin (x) / x =1

but, what about that.

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# Sin [Pi. (x-1)] / x-1; for x =1,2,3, .N

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