sinA + sinB + sinC <= (3 x 3^0.5 )/2//<![CDATA[ aax_getad_mpb({ "slot_uuid":"f485bc30-20f5-4c34-b261-5f2d6f6142cb" }); //]]>

how do we prove it?

A,B,C are angles of a triangle.

thanks for any help.

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# SinA + sinB + sinC <= (3 x 3^0.5 )/2

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