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The distance between the incident point and the refracted point

  1. May 19, 2016 #1
    1. The problem statement, all variables and given/known data
    The incidence angle of a light ray over a tile of glass with dy faces parallel is pi/3 rad. Find the distance between the incidence point and the refraction one of the ray with the tile, if the distance between these rays is 0.7 cm.

    2. Relevant equations

    3. The attempt at a solution
    sin pi/3/sinb=1.5/1 sinb=1/3
    tga=sqrt (2)/2 x=0.7*sqrt(2)/2=0.5
  2. jcsd
  3. May 20, 2016 #2


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    Hi Zade,
    Your post is a bit hard to follow, since you don't list the meanings of the symbols you use - and I don't see any in the drawing (which suggests 60 degrees is halfway between 0 and 90 degrees ?). Furthermore $$\sin{\pi\over 3}\ne {1\over 2}$$

    You don't really ask a question and end your post with '=0.5'. Do you think the distance the exercise asks for is 0.5 cm ?
  4. May 20, 2016 #3


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    Perhaps it would help if you marked on your diagram (or on a diagram); the 0.7cm and the distance to be calculated.

    You don't mention any refractive indices: are you assuming air=1 (I assume it's air) and glass = 1.5 ?
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