The incidence angle of a light ray over a tile of glass with dy faces parallel is pi/3 rad. Find the distance between the incidence point and the refraction one of the ray with the tile, if the distance between these rays is 0.7 cm.
The Attempt at a Solution
sin pi/3/sinb=1.5/1 sinb=1/3
tga=sqrt (2)/2 x=0.7*sqrt(2)/2=0.5