How to Prove the Sine Rule Using Cross Product?

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The discussion explains how to prove the sine rule using the cross product in vector form. It starts with the area of a triangle expressed as A = 1/2 * |a x b|, leading to the relationships A = 1/2 * ab sin C, A = 1/2 * bc sin A, and A = 1/2 * ca sin B. By equating these expressions, it derives the sine rule: sin A/a = sin B/b = sin C/c. The proof utilizes the properties of vector addition and cross products, confirming that the relationships hold true for the sides and angles of triangle ABC. This method effectively demonstrates the sine rule through vector analysis.
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Could anyone tell me how to use the cross product to prove the sine rule
 
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Area of a triangle of side a.b and c is
A = 1/2*axb = 1/2absinC
Similarly 1/2*bxc = 1/2 bcsinA and so on
So
absinC = bcsinA = casinB. Dividing abc to all we get
sinA/a = sinB/b = sinC/c
 
Here AB,BC,CA ,a,b,c are vectors and AB=a BC=b CA=c
in a triangle ABC,
AB + BC + CA = 0
a + b + c= 0
a x b =b x c = c x a(proved using above statement just take b and c to other side and take crossproduct with b on both sides first and then with c)
la x bl= |b x c|= |c x a |
|a||b| SinC= |b||c|SinA=|a||c| SinB
dividing by |a||b||c|
we get Sine formula
 
Last edited:

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