Single Slit Diffraction find central maximum

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SUMMARY

The discussion focuses on calculating the angular width of the central maximum in single slit diffraction. For a slit width of 1.50 µm illuminated by light of wavelength 500.0 nm, the angular width can be determined using the formula θ = λ/a, where λ is the wavelength and a is the slit width. Additionally, the width of a slit can be calculated from the half-width of the central maximum observed at a distance of 2 m when microwaves of wavelength 2.8 cm are used, although the initial calculations presented by the user were incorrect.

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Peter G.
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Hi,

I have tried tackling these question but I am simply absolutely lost...

1. A single slit of width 1.50 um is illuminated with light of wavelength 500.0 nm. Find the angular width of the central maximum.

I have no attempt for number 1.

2. Microwaves of wavelength 2.8 cm fall on a slit and the central maximum at a distance 2 m from the slit is found to have a half width of 0.67 m. Find the width of the slit.

Well, I tried to find the angle by dividing 0.67/1. To find the slit width I then dividing 0.028 by 0.67. But my answer was wrong according to the book.

Any help is appreciated.

Thanks,
Peter G.
 
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