SinX is defined for any angles [0,∞) ?

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In summary, the sine function, sinX, is defined for all angles, including negative angles. The textbook may be incorrect in stating that the domain is [0, ∞), when it is actually [-π/2, π/2]. Additionally, the statement "sinX = -sinX" does not hold true for all values of x, as it would imply that the sine function is equal to 0.
  • #1
solve
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SinX is defined for any angles [0,∞) ?

Homework Statement



SinX is defined for any angles [0,∞)

Homework Equations



Ok, the domain of sinX is -∞< x < ∞

The Attempt at a Solution



Someone said "You are confused due to fact that Sin(-x)= - sin(x)." Does it mean that just because sinX is not exactly -sinX, sinX will be undefined for all the negative angles since they will produce negative sine function values and we are only interested in positive sine function?

Thanks.
 
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  • #2


solve said:

Homework Statement



SinX is defined for any angles [0,∞)
Are you referring to the restricted sine function, "Sin x"? If so, the domain of Sin x isn't [0,∞), but [-π/2, π/2].
 
  • #3


eumyang said:
Are you referring to the restricted sine function, "Sin x"? If so, the domain of Sin x isn't [0,∞), but [-π/2, π/2].

This is from my textbook:

Start with the circle generated by the endpoint A of a straight line OA of unit length rotating anticlockwise about the end O. For angles X where 0<x<pi/2 radians you already know that sinX=AB/AO=AB since AO=1.

That is, the value of the trig ratio sinX is equal to the height of A above B. The sine function with output sinX is now defined as the height of A above B for any angle X (0≤x<∞)
 
  • #4


To me it just looks like your textbook is wrong... The sine function is certainly defined for negative angles too (as well as complex numbers, if you know what those are...)

Your statement in 3. makes no sense, since the sine function takes on negative values for some positive x too. But anyway, there are no such restrictions on functions in general, the so-called odd functions (like sin(x)) and even functions (like cos(x)) are special cases. Also, if sin(x) = - sin(x), then sin(x) = 0 ...
 
  • #5


niklaus said:
To me it just looks like your textbook is wrong... The sine function is certainly defined for negative angles too (as well as complex numbers, if you know what those are...)

Your statement in 3. makes no sense, since the sine function takes on negative values for some positive x too. But anyway, there are no such restrictions on functions in general, the so-called odd functions (like sin(x)) and even functions (like cos(x)) are special cases.

Indeed, sin((3 * pi) / 2) = -1. Weird.

niklaus said:
Also, if sin(x) = - sin(x), then sin(x) = 0 ...

I have to think about how this ties with the rest.
 
  • #6


It doesn't. If A= -A, then, adding A to both sides, 2A= 0 so, dividing both sides by 2, A= 0. That has nothing to do with trig functions.
 

1. What is the meaning of "SinX is defined for any angles [0,∞) "?

The statement means that the sine function, denoted as SinX, can be used to find the ratio of the length of the side opposite an angle to the length of the hypotenuse for any angle between 0 and infinity degrees. This is possible because the sine function is a periodic function, meaning it repeats its values after a certain interval.

2. How is the value of SinX determined for angles [0,∞) ?

The value of SinX is determined using a mathematical formula, where the sine of an angle is equal to the ratio of the opposite side to the hypotenuse. This formula is applicable for all angles in the interval [0,∞), and can be calculated using a calculator or trigonometric tables.

3. Can SinX be negative for angles in the interval [0,∞) ?

Yes, SinX can be negative for angles in this interval. This is because the sign of the sine function depends on the quadrant in which the angle lies. In the first and second quadrants, SinX is positive, while in the third and fourth quadrants, it is negative.

4. What is the maximum value of SinX for angles in the interval [0,∞) ?

The maximum value of SinX for angles in this interval is 1. This occurs when the angle is 90 degrees or π/2 radians. In other words, the sine of an angle cannot be greater than 1 for any angle between 0 and infinity degrees.

5. Are there any limitations to using SinX for angles in the interval [0,∞) ?

One limitation to using SinX for angles in this interval is that it only applies to right triangles. Additionally, it may not accurately represent angles greater than 360 degrees or 2π radians, as the sine function repeats its values after this interval. Therefore, for angles greater than 360 degrees, other mathematical techniques may be necessary to find the sine value.

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