MHB Sketch of the Reflection Transformation of a Parallelogram

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The discussion focuses on the linear transformation that reflects points through the x2 axis, represented by the matrix T. It provides calculations for the transformation of specific vectors, demonstrating that T preserves vector addition and maps the zero vector to itself. Two sketches illustrating the transformation properties are mentioned, with Geogebra identified as the software used for creating the drawings. The transformation results in negative x-coordinates while retaining y-coordinates. Overall, the conversation emphasizes the mathematical properties of the reflection transformation in a parallelogram context.
bwpbruce
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$\textbf{Problem:}$
Let $T: \mathbb{R}^2 \rightarrow \mathbb{R}^2$ be the linear transformation that reflects each point through the $x_2$ axis. Make two sketches that illustrate properties of linear transformation.

$\textbf{Solution:}$
Let $T(\textbf{x}) = \begin{bmatrix} -1 & 0 \\ 0 & 1 \end{bmatrix}\begin{bmatrix} x_1 \\ x_2 \end{bmatrix} = \begin{bmatrix} -x_1 \\ x_2 \end{bmatrix}$

Let
$\textbf{u} = \begin{bmatrix} 3 \\ 4 \end{bmatrix}, \textbf{v} = \begin{bmatrix} 4 \\ 3 \end{bmatrix}$
And $\textbf{u + v} = \begin{bmatrix} 7 \\ 7 \end{bmatrix}$

Then
$T\textbf{u} = \begin{bmatrix} -1 & 0 \\ 0 & 1 \end{bmatrix}\begin{bmatrix} 3 \\ 4 \end{bmatrix} = \begin{bmatrix} -3 \\ 4 \end{bmatrix}$
$T\textbf{v} = \begin{bmatrix} -1 & 0 \\ 0 & 1 \end{bmatrix}\begin{bmatrix} 4 \\ 3 \end{bmatrix} = \begin{bmatrix} -4 \\ 3 \end{bmatrix}$
$T\textbf{u + v} =\begin{bmatrix} -7 \\ 7 \end{bmatrix}$
$T\textbf{(0)} = \textbf{0}$

View attachment 3893
 

Attachments

  • Axis Reflection.png
    Axis Reflection.png
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  • Reflection About X_2 Axis.png
    Reflection About X_2 Axis.png
    6.2 KB · Views: 112
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Seems good to me. Which software did you use to make the drawing?
 
Evgeny.Makarov said:
Seems good to me. Which software did you use to make the drawing?

Geogebra
 
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