- #1

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if you set them equal to each other you get 6|x| = x^2 - 7

but im not exactly sure what to do with the |x|

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- Thread starter apiwowar
- Start date

- #1

- 96

- 0

if you set them equal to each other you get 6|x| = x^2 - 7

but im not exactly sure what to do with the |x|

- #2

- 378

- 2

http://www.padowan.dk/graph/

but even without, you can take two cases x>=0, x<0 .. and solve them

- #3

- 11

- 0

f(x) = 6x for x >= 0

-6x for x < 0

Or you could notice that the two functions are even, and you could thus solve for x using 6x, and keep in mind that there is another intersection point opposite the y-axis.

- #4

HallsofIvy

Science Advisor

Homework Helper

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If [itex]x\ge 0[/itex], |x|= x so this is 6x= x^2- 7 which is the same as x^2- 6x- 7= 0.

if you set them equal to each other you get 6|x| = x^2 - 7

but im not exactly sure what to do with the |x|

If x< 0, |x|= -x so this is -6x= x^2- 7 which is the same as x^2+ 6x- 7= 0.

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