- #1
1337Montage
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Homework Statement
Homework Equations
a=v/t
v=d/t
Sketching An Acceleration-Time Graph From A Velocity-Time Graph
- Thread starter 1337Montage
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The discussion focuses on deriving an acceleration-time graph from a velocity-time graph, confirming that a negative slope in the velocity graph indicates a straight line for acceleration. Participants agree that the reasoning behind the negative acceleration is correct, reinforcing the relationship between velocity and acceleration. The conversation highlights confidence in understanding basic calculus principles related to motion. Overall, the consensus is that the interpretation of the graphs is accurate and well-supported. The collaborative nature of the discussion emphasizes the importance of peer feedback in solving physics problems.
a=v/t
v=d/t
- #2
MysticDude
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I believe that that is correct because since the velocity has the same negative slope, the acceleration should be a straight line. And in your attempt, the acceleration is negative and just a line, that answer is correct I believe.
- #3
The legend
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yup .. has to be correct... MysticDude's reasoning looks right too.
- #4
MysticDude
Gold Member
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The legend said:
Alright, I guess I know my calculus basics eh? Oh and thanks for the friend request.
- #5
1337Montage
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Yep, it's correct. Thank you for your help guys.
The answer is (B) but I don't really understand why.
Based on formula of Young Modulus:
$$x=\frac{FL}{AE}$$
The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A##
I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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