Sketching An Acceleration-Time Graph From A Velocity-Time Graph

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The discussion focuses on deriving an acceleration-time graph from a velocity-time graph, confirming that a negative slope in the velocity graph indicates a straight line for acceleration. Participants agree that the reasoning behind the negative acceleration is correct, reinforcing the relationship between velocity and acceleration. The conversation highlights confidence in understanding basic calculus principles related to motion. Overall, the consensus is that the interpretation of the graphs is accurate and well-supported. The collaborative nature of the discussion emphasizes the importance of peer feedback in solving physics problems.
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Homework Statement


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Homework Equations


a=v/t
v=d/t


The Attempt at a Solution


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I believe that that is correct because since the velocity has the same negative slope, the acceleration should be a straight line. And in your attempt, the acceleration is negative and just a line, that answer is correct I believe.
 
yup .. has to be correct... MysticDude's reasoning looks right too.
 
The legend said:
yup .. has to be correct... MysticDude's reasoning looks right too.

Alright, I guess I know my calculus basics eh? Oh and thanks for the friend request.
 
Yep, it's correct. Thank you for your help guys.
 

Thread 'Magnitude of buoyant force in fluids of different densities'

The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?
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