Sketching Root Locus of System: K Varies 0 to ∞

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SUMMARY

The discussion focuses on sketching the root locus of a control system as the gain K varies from 0 to infinity. The characteristic equation derived is (s+2)(s+5)(s+K) + 10K = 0, which expands to s³ + 7s² + 10s + K(s² + 7s + 20) = 0. The root locus is determined by identifying the poles at p1=0, p2=-2, and p3=-5, and the zeros at z1=3.5 + 2.8i and z2=3.5 - 2.8i. The final form of the characteristic equation is expressed as 1 + K(s² + 7s + 20)/(s³ + 7s² + 10s) = 0.

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weavertri
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Hello guys, I need help to sketch the root locus of the system when K is varying from 0 to infinity. (K>=0)
The system:
http://www.freeimagehosting.net/newuploads/anspe.jpg

I'm stuck. I really don't know how proceed.
Thanks in advance.
 
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Plot the poles and zeroes (There are no zeroes here). Use the root locus drawing rules.
 
yeah, that's what I'm doing... the problem is: K is not a constant. to use the root locus drawing rules the characteristic equation of the closed loop system must be written as 1 + GH = 0. All that I got in this case is
(s+2)(s+5)(s+K) + 10K = 0.
 
I guess I finally did it.
my characteristic equation is (s+2)(s+5)(s+K) + 10K = 0.
we expand to s³ + 7s² + 10s + Ks² 7Ks + 20K = 0
the C.E. must be written as 1 + K*F(s) = 0, then

s³ + 7s² + 10s + K(s² + 7s + 20) = 0

1 + K(s² + 7s + 20)/( s³ + 7s² + 10s) = 0



this is equal to

1 + K(s + 3.5 - 2.8i)(s + 3.5 + 2.8i)/(s(s+2)(s+5)) = 0


now we can sketch the root locus where the zeros are (z1= 3.5 + 2.8i and z2 = 3.5 - 2.8i) and the poles p1=0, p2=-2 and p3=-5.

:)
 

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