Sketching these curves is a form of madness! How can I make sense of them?

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Homework Help Overview

The original poster is tasked with sketching two curves defined by the equations x + y - y³ = 0 and x - y + y² = 0, and finding their points of intersection. The subject area involves algebraic manipulation and curve sketching in the context of implicit functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss transforming the equations into the form x = f(y) to facilitate sketching. Questions are raised about general characteristics of the curves without plotting, particularly regarding the behavior of the cubic term.

Discussion Status

Some participants suggest methods for determining the intersection points by equating the expressions for x derived from both equations. There is an ongoing exploration of how to visualize the curves effectively, with no explicit consensus on a single approach yet.

Contextual Notes

The original poster expresses uncertainty about the shapes of the curves and seeks guidance on understanding functions in this form. There is a hint of confusion regarding the dependency of the y-axis in the context of sketching.

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Homework Statement



I need to sketch these curves and find where they intersect:

x+y-y^3 = 0
x-y+y^2=0


Homework Equations





The Attempt at a Solution



I have no idea what these are supposed to look like.. other than that x = -y^2+y is a sort of parabola that opens to the right.

Any tips as to how to understand functions in these forms?
 
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These are easy, because you can get them in the form x=f(y). Just compute x for different values of y.
 
Any general rule about how these look like without plotting the points?
(Like for the thing with y^3?)
 
The first equation can be written as x = y3 - y, and the second as x = y2 - y. At a point of intersection point, the x-value on one curve has to equal the x-value on the other curve, and the same is true for the y-values.

Setting the two expressions for x equal gives us
y3 - y = y2 - y
This is simple to solve, and you don't need to plot any points to do it.
 
He says he needs to sketch the curve as well, though.

Quit thinking that the y-axis must be dependent. Pick some y points and find where the x values are at those points. You'll figure out the shape.
 

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