Sketching Vector Function: -yx'+xy

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SUMMARY

The discussion focuses on sketching the vector function V = -yx' + xy'. Participants emphasize the importance of associating a vector with each point on the xy-plane, highlighting the need to determine both the magnitude and direction of the vector field. Key methods include calculating the magnitude using |V| = √(V_x² + V_y²) and the direction using the unit vector formula \hat V = \vec V / |V|. Additionally, utilizing polar coordinates and the curl (rotor) of the function are recommended for a comprehensive understanding of the vector field's behavior.

PREREQUISITES
  • Understanding of vector functions and their representation in the xy-plane
  • Familiarity with calculating magnitude and direction of vectors
  • Knowledge of polar coordinates and their application in vector analysis
  • Basic understanding of curl (rotor) in vector calculus
NEXT STEPS
  • Learn how to calculate vector field magnitudes and directions in detail
  • Explore the application of polar coordinates in vector analysis
  • Study the concept of curl (rotor) and its significance in vector fields
  • Review vector field visualization techniques, such as those found in the provided tutorial
USEFUL FOR

Students studying vector calculus, mathematicians, and anyone interested in visualizing and analyzing vector fields in the xy-plane.

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Homework Statement



Sketch a function V= -yx'+xy' ?

Homework Equations





The Attempt at a Solution



i have compared it with r= xi'+yj'. and putting different values of y and x to sketch it on y -axis and x axis. is it correct. how should i do it.
 
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You have here a vector function of x and y, that means that with every point on the xy plane, there is associated a vector, with magnitude and direction.
I suggest you find both of these separately and then sketch your diagram using something like this method:

http://tutorial.math.lamar.edu/Classes/CalcIII/VectorFields.aspx

Each little arrow starts at the point it describes, and gives both the direction of the vector field there, and its relative magnitude (Longer arrows for greater values of the magnitude)

Can you find the magnitude and direction of a general point of the vector field?

For the magnitude:
[tex]|V| = \sqrt{V_x^2 + V_y^2}[/tex]

For the direction:
[tex]\hat V = \frac{\vec V}{|V|}[/tex]

After you get the direction you may find it useful to look at it using polar coordinates. That should make the orientation of the direction very clear when you compare it with the simple radial direction: [tex]\hat r = \cos{\theta} \hat x + \sin{\theta} \hat y[/tex]
Try and rearrange what you get into the form [tex]\hat V = \cos{(\theta + \phi)} \hat x + \sin{(\theta + \phi)}\hat y[/tex] and then you'll see by how much to rotate the radial unit vector to get the direction at the point.

If you know how to take the curl (rotor) of a function, you may find that tool helpful here for a qualitative feel of what this field is like.

For a complete explanation on the subject (With your particular example in use, even!) :
http://math.etsu.edu/Multicalc/Chap5/Chap5-1/part4.htm
 
Last edited by a moderator:
Thanks .. i got it.. really good explanation
 

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