Ski Slope using Energy Conservation

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SUMMARY

The discussion revolves around a physics problem involving energy conservation on a ski slope. Julie starts at the top of a 60-degree slope, and the goal is to determine how far horizontally she lands after launching off a 3.0-meter-high ramp. Key equations include gravitational potential energy (Ug = mgh) and kinetic energy (K = 0.5mv²). The participant initially struggles with the mass variable but realizes it cancels out, allowing for the calculation of velocity and subsequent horizontal distance.

PREREQUISITES
  • Understanding of gravitational potential energy (Ug = mgh)
  • Familiarity with kinetic energy equations (K = 0.5mv²)
  • Basic knowledge of kinematics equations
  • Concept of energy conservation in physics
NEXT STEPS
  • Study the principles of energy conservation in mechanical systems
  • Learn how to apply kinematics equations to projectile motion
  • Explore the effects of launch angles on projectile trajectories
  • Review examples of energy conservation problems in physics textbooks
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators looking for practical examples of applying theoretical concepts in real-world scenarios.

merzperson
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Homework Statement



It's been a great day of new, frictionless snow. Julie starts at the top of the 60 degree slope shown in the figure . At the bottom, a circular arc carries her through a 90 turn, and she then launches off a 3.0--high ramp. How far horizontally is her touchdown point from the end of the ramp?

10.P49.jpg


Homework Equations



Ug = mgh
K = 0.5mv2
Kinematics equations

The Attempt at a Solution



I know I need to use energy conservation to find the kinetic energy at the end of the ramp so I can find the velocity of the skier then, but I do not know how I can find Ug at the top of the ramp without knowing the skier's mass (too many unknowns). Once I know the initial Ug or Kmax I know how to solve the problem, but I'm having trouble getting there.
 
Last edited:
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Never mind the mass, it will cancel. Just use m for the mass or any number you like.

ehild
 
Thanks ehild, got it.
 
Just wondering how the launch angle is determined in this question?
 

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