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Skier at the top of a hill

  1. Oct 10, 2012 #1
    1. The problem statement, all variables and given/known data A skier starts from rest at the top of a hill. The skier coasts down the hill and up a second hill,The crest of the second hill is circular, with a radius of r = 38.5m. Neglect friction and air resistance. What must be the height h of the first hill so that the skier just loses contact with the snow at the crest of the second hill?

    2. Relevant equations ke=1/2mv^2 and pe=mgh
    e=pe+ke


    3. The attempt at a solution e=0 so pe =ke and h=(H-2r) and v^2=gr
    so i found h=2r+r/2 and i got 96.25 m but its not right please help
     
  2. jcsd
  3. Oct 10, 2012 #2
    ok wait i think i found my problem it should be mgh=1/2mgr so h=1/2r.....
     
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