Skier at the top of a hill

[omc1]

Homework Statement

A skier starts from rest at the top of a hill. The skier coasts down the hill and up a second hill,The crest of the second hill is circular, with a radius of r = 38.5m. Neglect friction and air resistance. What must be the height h of the first hill so that the skier just loses contact with the snow at the crest of the second hill?

Homework Equations

ke=1/2mv^2 and pe=mgh
e=pe+ke

The Attempt at a Solution

e=0 so pe =ke and h=(H-2r) and v^2=gr
so i found h=2r+r/2 and i got 96.25 m but its not right please help

 

[omc1]

ok wait i think i found my problem it should be mgh=1/2mgr so h=1/2r...