- #1

Roadman20

- 4

- 0

## Homework Statement

You've skied down a slope and are going 20m/s when you hit the base of a slope that is 30 degree incline.?

Assuming friction and drag are negligible, how much altitude (y) will you gain as you’re slowing down?

How far up the 30 degree slope (∆x along the incline) will you coast before you stop?

I know the following variables:

vi = 20 m/s

vf = 0 m/s

angle is 30°

I know the skier's energy is kinetic changing to potiential gravitational energy.

## Homework Equations

Ki → Ug

KE = 1/2*m*v^2

PE = m*g*h

For a)

It seems like I need to use 20tan30, but I'm not sure.

For b)

need ma = mgsin(theta) to solve for a = gsin(theta)

and vf^2 = vi^2+2*a*d → d = -vf^2 + vi^2 + 2a

## The Attempt at a Solution

For a) 20*tan(30°) = 17.32

For b) (-9.8)sin(30°) = -4.9

d = 0 + (20)^2 + 2(-4.9)

d = 40 + (-9.8)

d= 30.2