You've skied down a slope and are going 20m/s when you hit the base of a slope that is 30 degree incline.?
Assuming friction and drag are negligible, how much altitude (y) will you gain as you’re slowing down?
How far up the 30 degree slope (∆x along the incline) will you coast before you stop?
I know the following variables:
vi = 20 m/s
vf = 0 m/s
angle is 30°
I know the skier's energy is kinetic changing to potiential gravitational energy.
Ki → Ug
KE = 1/2*m*v^2
PE = m*g*h
It seems like I need to use 20tan30, but I'm not sure.
need ma = mgsin(theta) to solve for a = gsin(theta)
and vf^2 = vi^2+2*a*d → d = -vf^2 + vi^2 + 2a
The Attempt at a Solution
For a) 20*tan(30°) = 17.32
For b) (-9.8)sin(30°) = -4.9
d = 0 + (20)^2 + 2(-4.9)
d = 40 + (-9.8)