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Slanted Gravity: A boy on a hill

  1. Aug 6, 2008 #1
    1. The problem statement, all variables and given/known data
    A boy stands at the peak of a hill which slopes downward uniformly at angle [tex] \phi [/tex]. At what angle [tex] \theta [/tex] from the horizontal should he throw a rock so that is has the greatest range.

    (Source: Introduction to Mechanics by Kleppner and Kolenkow)
    2. Relevant equations
    I suppose trig identities, vectors, and the general one dimensional kinematics would help ([tex]x_0+v_0t+a_0t^2[/tex])

    3. The attempt at a solution
    Now my solution went like this: Pretend the ground is flat and that instead gravity is at an angle [tex]\phi-90)[/tex], and that the ball is launch at angle [tex]\theta+\phi[/tex] My idea was to decompose both the gravity vector and the vector of the launch into vertical and horizontal vectors, look at the time it takes to hit the ground using the vertical component and then use that time to plug into see how far it goes in the horizontal component. Then, simply maximize that with respect to [tex]\theta[/tex]. If you draw it out and do all that, you get:


    Vertical components:
    Initial Velocity: [tex]v_0\sin{(\theta+\phi)}[/tex]
    Acceleration from Gravity: [tex]-g\cos{\phi}[/tex]

    Horizontal components:
    Initial Velocity: [tex]v_0\cos{(\theta+\phi)}[/tex]
    Acceleration: [tex]+g\sin{\phi}[/tex]

    Time to hit ground:

    Now plug that [tex]t[/tex] into:

    and maximize. Now from pure, unrelated experimentation, I also get [tex]\theta=\frac{90-\phi}{2}[/tex] to maximize the distance.

    Now my questions are

    1) Is there anything wrong with my method? It's not a priority question but it would be useful
    2) Is there a better way to do this? This solution is very messy and I was wondering if there was a more elegant, creative way to solve this. :)
    3) Are both answers that I obtained above correct?

    Thanks a lot

    (I realize that another thread was made about this a year ago, but that never went anywhere, the problem was not solved, and the methods attempted was completely different, etc. so I thought it would be better simply to create a new topic. Merge if necessary: https://www.physicsforums.com/showthread.php?t=201484 )
    Last edited: Aug 6, 2008
  2. jcsd
  3. Aug 7, 2008 #2


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    Homework Helper

    Welcome to PF!

    Hi Anaxerzia ! Welcome to PF! :smile:
    What you are doing is using p and q coordinates (say), where p = x cosφ + y sinφ, q = y cosφ - x sinφ

    Yes, that's a perfectly valid method! :smile:

    (But "pretend the ground is flat" is not mathematical language! :wink:)
  4. Aug 7, 2008 #3
    Or I guess you could have said to rotate by [tex]\phi[/tex] , right? :-)

    Does anyone have a more elegant solution? It seems to be lurking in there somewhere...
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