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1. Homework Statement
A 5.50 kg block (m1) is connected by means of a massless rope to a 3.15 kg block (m2). The pulley is frictionless. Calculate the maximum value for the coefficient of static friction, if the 5.50 kg block is to begin sliding.
The diagram is attatched to the post.
2. Homework Equations
Friction coefficient = (Frictional Force)/(Normal Force)
Acceleration = (m2*9.8)/(m1 + m2)
Of course, Force = mass*acceleration
3. The Attempt at a Solution
Acceleration = (m2*9.8)/(m1 + m2)
Acceleration = 3.5688 m/s^2
3.5688*5.5 = 19.6284 N = frictional force
Normal force = 5.5*9.8 = 53.9 N
19.6284/53.9 = .36416
I know that the answer isn't right, what am I doing wrong?
A 5.50 kg block (m1) is connected by means of a massless rope to a 3.15 kg block (m2). The pulley is frictionless. Calculate the maximum value for the coefficient of static friction, if the 5.50 kg block is to begin sliding.
The diagram is attatched to the post.
2. Homework Equations
Friction coefficient = (Frictional Force)/(Normal Force)
Acceleration = (m2*9.8)/(m1 + m2)
Of course, Force = mass*acceleration
3. The Attempt at a Solution
Acceleration = (m2*9.8)/(m1 + m2)
Acceleration = 3.5688 m/s^2
3.5688*5.5 = 19.6284 N = frictional force
Normal force = 5.5*9.8 = 53.9 N
19.6284/53.9 = .36416
I know that the answer isn't right, what am I doing wrong?
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