Sliding mass on sliding incline

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SUMMARY

The discussion centers on the dynamics of a block of mass m sliding down a frictionless incline on a triangular block of mass M, which is free to slide on a horizontal plane. The user derived the horizontal force as F(horizontal) = mg cos θ sin θ and calculated the acceleration of mass M as a(M, horizontal) = F(horizontal) / (m + M). However, the response indicates that the user needs to consider the relationship between the accelerations of both blocks and their directional components to arrive at the correct solution.

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zheng89120
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Homework Statement



A block of mass m slides down the incline of a triangular block of mass M. The angle of inclination is \theta. The trianguilar block is free to slide on a horizontal plane. Assume that all surfaces are frictionless. What is the acceleration of the mass M?

Homework Equations



F(net)=ma=0

The Attempt at a Solution



so basically i want to ask if my answer is correct, as I'm not familiar with this type of problem, i got:

F(horizontal) = mg cos \theta sin \theta
a(M, horizontal) = F(horizontal) / (m + M)

is this right?
 
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zheng89120 said:

Homework Statement



A block of mass m slides down the incline of a triangular block of mass M. The angle of inclination is \theta. The trianguilar block is free to slide on a horizontal plane. Assume that all surfaces are frictionless. What is the acceleration of the mass M?

Homework Equations



F(net)=ma=0

The Attempt at a Solution



so basically i want to ask if my answer is correct, as I'm not familiar with this type of problem, i got:

F(horizontal) = mg cos \theta sin \theta
a(M, horizontal) = F(horizontal) / (m + M)

is this right?
Not quite. Are the accelerations of the 2 blocks the same? What about the direction of the accelerations?
 

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