Slope Amplitude: Physics Help for Newbs

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SUMMARY

The discussion focuses on understanding the implications of slope in various graphs related to simple harmonic motion (SHM), specifically period versus amplitude, length, and mass. It is established that the slope of the period versus amplitude and period versus mass graphs is zero, indicating no dependence of period on these variables. Conversely, the period versus length graph demonstrates a non-linear relationship, and when period squared is plotted against length, a linear relationship emerges with a slope of 4π²/g. The conversation emphasizes the importance of correctly plotting these relationships to derive meaningful conclusions.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM)
  • Familiarity with graphing techniques in physics
  • Knowledge of the formula T = 2π√(l/g)
  • Ability to calculate slope from graphs
NEXT STEPS
  • Research the relationship between period and amplitude in simple harmonic motion
  • Learn about the derivation of the period of a pendulum
  • Explore the concept of phase in oscillatory motion
  • Investigate the significance of plotting period squared against length
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillations, as well as educators seeking to enhance their understanding of simple harmonic motion and graph interpretation.

boberth2o
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Ok as I am a Newb at pyshics I need some help with my homework. *sigh* This is going to be a couple of de de de questions. And here we go:

1. What does the slope indicate on a period(time) vs. amplitude(degrees) graph?
2. What does the slope indicate on a period(time) vs. length(cm) graph?
3. What does the slope indicate on a period(time) vs. mass(g) graph?
 
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Welcome to the physics forums boberth2o! We do not provide full homework solutions here as the student will learn nothing. The student must show some effort at solving the questions.

What do you think the gradient of each graph indicates? Think of how you determine the gradient or slope.

P.S you posted in the wrong forum, there are homework forums located here:

https://www.physicsforums.com/forumdisplay.php?f=152
 
Kurdt said:
Welcome to the physics forums boberth2o! We do not provide full homework solutions here as the student will learn nothing. The student must show some effort at solving the questions.

What do you think the gradient of each graph indicates? Think of how you determine the gradient or slope.

P.S you posted in the wrong forum, there are homework forums located here:

https://www.physicsforums.com/forumdisplay.php?f=152

Thanks, I searched througth the main forum searching for somthing like this but I must of missed it.

Well I am not fishing for answers, here's what I am doing, I am writing a report in the 'formal laboratory report' format. Under analysis I have to determine what the slope indicates. At this point I can't seem to come up with the answer. I know to determine the slope, its the portion under the graph (correct?). If you could goad me into the right direction I might be able to find it myself.
 
The gradient or slope of the graph tells you the rate of change of the graph at a particular point. When you first come across it at school it will be finding the slope of straight line graphs, where you measure the change in y and change in x and divide them. In other words:

gradient = \frac{\Delta y}{\Delta x}

So for your graphs what physical quantity would you arrive at if you divided the y-axis by the x axis.
 
Kurdt said:
The gradient or slope of the graph tells you the rate of change of the graph at a particular point. When you first come across it at school it will be finding the slope of straight line graphs, where you measure the change in y and change in x and divide them. In other words:

gradient = \frac{\Delta y}{\Delta x}

So for your graphs what physical quantity would you arrive at if you divided the y-axis by the x axis.

That would make it period/amplitude, how do I represent that? T/(degree sign)
 
I think you may have plotted your graphs wrongly. Normally time goes along the x-axis. an angle divided by time will be an angular speed, radians per second.
 
Kurdt said:
I think you may have plotted your graphs wrongly. Normally time goes along the x-axis. an angle divided by time will be an angular speed, radians per second.

Yes but amplitude it the manipulated variable, I was sure that the manipulated goes on the x-axis (max roy)
 
OK this looks like an SHM lab. Apologies I didn't pick up on that earlier. What exactly is the purpose of the lab may I inquire? I presume you are investigating period and have you been told to plot those graphs?
 
Kurdt said:
OK this looks like an SHM lab. Apologies I didn't pick up on that earlier. What exactly is the purpose of the lab may I inquire? I presume you are investigating period and have you been told to plot those graphs?

We are making a lab on the pendulums swing, how the mass, length, and amplitude affect the swing.
The Pendulum is set a 10 degrees and dropped, once the pendulum reaches zero degrees or perfectly up and down, we time how long it takes to get ten full swings in. Then manipulating the parameters we do it again and again. Now using the average of the data (three trails for each variable) we graph the results.
 
  • #10
I wonder if you've ever derived the period of a pendulum before? For a simple pendulum a lot of things cancel out and one obtains the familiar equation:

T = 2\pi\sqrt{\frac{l}{g}}

Hidden among that in the assumptions and the derivation are the quantities you're dealing with, namely mass and amplitude expressed as angle and the mass of the pendulum. I will say that to gain anything useful out of the graphs you may have to do them again. You will notice that the equation gave above for period isn't directly proportional to the length.

I'll be offline after this since its quite late where I am, but I'll direct some other homework helpers here.
 
  • #11
Kurdt said:
I wonder if you've ever derived the period of a pendulum before? For a simple pendulum a lot of things cancel out and one obtains the familiar equation:

T = 2\pi\sqrt{\frac{l}{g}}

Hidden among that in the assumptions and the derivation are the quantities you're dealing with, namely mass and amplitude expressed as angle and the mass of the pendulum. I will say that to gain anything useful out of the graphs you may have to do them again. You will notice that the equation gave above for period isn't directly proportional to the length.

I'll be offline after this since its quite late where I am, but I'll direct some other homework helpers here.

Thank you but all I need to figure out is the word(s) that describe the period/amplitude. like the example displacemnet on a time velocity graph.
 
  • #12
instead of amplitude, do you mean PHASE?
 
  • #13
robphy said:
instead of amplitude, do you mean PHASE?

No I was told to use amplitude.
 
  • #14
Ok, for graphs 1 and 3 you should get a horizontal straight line graph. The slope of this is 0 and this indicates that period has no dependence on amplitude or mass. For period length, you should get a curve which indicates a non linear dependence, and if you plot period squared against length you will get a straight line graph, the slope of which will be:

\frac{4\pi^2}{g}

I suppose my confusion arose from the fact that normally one plots a period squared length graph.
 
  • #15
Kurdt said:
Ok, for graphs 1 and 3 you should get a horizontal straight line graph. The slope of this is 0 and this indicates that period has no dependence on amplitude or mass. For period length, you should get a curve which indicates a non linear dependence, and if you plot period squared against length you will get a straight line graph, the slope of which will be:

\frac{4\pi^2}{g}

I suppose my confusion arose from the fact that normally one plots a period squared length graph.

Well the funny thing is that I handed in that report today and then took note on this very stuff, mostly SHM.
 

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