Slope of the tangent line of an intersection - Directional Derivatives

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SUMMARY

The discussion focuses on finding the slope of the tangent line at the intersection of the vertical plane defined by the equation x - y + 1 = 0 and the surface z = x² + y² at the point (1, 2, 5). The solution involves calculating the gradients of both the plane and the surface, followed by taking the cross product of these gradients to determine the direction of the tangent line. The directional derivative is then used to find the slope in the horizontal direction of the plane.

PREREQUISITES
  • Understanding of gradient vectors in multivariable calculus
  • Knowledge of cross products in vector calculus
  • Familiarity with directional derivatives
  • Ability to work with equations of planes and surfaces
NEXT STEPS
  • Study how to compute gradients for multivariable functions
  • Learn about the cross product and its geometric interpretation
  • Research the concept of directional derivatives and their applications
  • Explore examples of tangent lines to curves of intersection in 3D space
USEFUL FOR

Students and educators in calculus, particularly those focusing on multivariable functions, vector calculus, and applications of gradients and directional derivatives.

RaoulDuke
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Homework Statement


Find the slope of the tangent line to the curve of intersection of the vertical plane x - y + 1 =0 and the surface z = x2+y2 at the point (1, 2, 5)


Homework Equations


Gradients, Cross products


The Attempt at a Solution



I'm pretty lost here. I think I have to cross the two gradients of the functions that I have to find the intersection at (1, 2, 5). However, what then?
 
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how about finding the horizontal direction of the plane, then using it to find the directional derivative...
 

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