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So basic question about Charge density on the surface of the conductor

  • Thread starter baby_1
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Hello
I want to know surface charge density of the conductor in all part of that is same or not?
for example in this shape ?
3065864600_1403087286.jpg

if isn't why and how the surface charge density spread?
Thanks
 

CAF123

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What are your thoughts? Compare the given shape to, say, a sphere. What is the difference?
 
138
5
Thanks dear CAF123
you mean surface charge density at different point of a conductor are the same? point 1 and 2 have same surface charge density?
7272210400_1403158339.jpg

if yes? why surface charge density should be same?
if no?how can find surface charge density at different point and different shape?
 

BvU

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Dear baby,

Just for my information: is there an external electric field ?

A (ideal) conductor is characterized by the fact that there are no potential differences between points on the surface. If there were, the charge would move until there are no more.

In the absence of an external field that means all electric field lines are perpendicular to the surface and equipotential lines parallel to it. Hence evenly distributed surface charge...
 

SammyS

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Dear baby,

Just for my information: is there an external electric field ?

A (ideal) conductor is characterized by the fact that there are no potential differences between points on the surface. If there were, the charge would move until there are no more.

In the absence of an external field that means all electric field lines are perpendicular to the surface and equipotential lines parallel to it. Hence evenly distributed surface charge...
Actually, it has a unevenly distributed surface charge.

For an isolated conducting sphere, the potential at the surface is given by [itex]\displaystyle V(R)=\frac{Q}{4\pi\epsilon_0 R}= \frac{\sigma R}{\epsilon_0}[/itex]

Consider each end of the conductor you show in the figure.

attachment.php?attachmentid=70728&stc=1&d=1403238050.jpg


The left end appears to be a section of a sphere with a relatively large radius. The right end a section of a sphere with much smaller radius.

It's clear that the surface charge density, σ, depends upon the radius of curvature.
 

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Dear baby,

Just for my information: is there an external electric field ?

A (ideal) conductor is characterized by the fact that there are no potential differences between points on the surface. If there were, the charge would move until there are no more.

In the absence of an external field that means all electric field lines are perpendicular to the surface and equipotential lines parallel to it. Hence evenly distributed surface charge...
I disagree. See SammyS' post.

Surface charge density is governed by equation :

σ1r12r2

when you connect two conductors. From here surface charge density is inversely related to the radius of conductor.

So at peaks charge density is maximum and it's unevenly distributed.
 

BvU

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I stand corrected for my last sentence! My "Hence evenly distributed surface charge... " wasn't thought through. Too many simple spherically symmetric exercises...

I hope the stuff before can stay standing, though ?
 

SammyS

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I stand corrected for my last sentence! My "Hence evenly distributed surface charge... " wasn't thought through. Too many simple spherically symmetric exercises...

I hope the stuff before can stay standing, though ?
Yup.

The potential is uniform throughout the conductor (under electrostatic conditions).
 

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