So the correct SI units for the quantity A are meters (m).

[tommyboo]

I am having a problem finding the correct SI unitsfor the quantity A?

In the equation

A=√(R/TY)

That is A equals the square root of R divided by TY

(not to good showing workings on the computer sorry)

, the SI units of the quantity R are kg m^3 s^–2, the SI units of the quantity T are kg and the SI units of the quantity Y are m s^–2. What are the correct SI units for the quantity A?

 

[Mark44]

I am having a problem finding the correct SI unitsfor the quantity A?

In the equation

A=√R/TY

That is A equals the square root of R divided by TY

Both your notation and explanation are ambiguous.

Is the expression on the right side this?
\sqrt{\frac{R}{TY}}
or this?
\frac{\sqrt{R}}{TY}

(not to good showing workings on the computer sorry)

, the SI units of the quantity R are kg m^3 s^–2, the SI units of the quantity T are kg and the SI units of the quantity Y are m s^–2. What are the correct SI units for the quantity A?

 

[tommyboo]

The first one R/ty all square root. Do apologise for the bad format

 

[gsal]

Then, the units of A are meters.

 

[zgozvrm]

To clarify gsal's answer...

You have the expression
\sqrt{\frac{R}{TY}}

Simply, insert the units for each variable (in place of the variables):
\sqrt{\frac{\frac{kg\cdot m^3}{s^2}}{(kg)(\frac{m}{s^2})}}

and simplify...
\sqrt{\left(\frac{kg \cdot m^3}{s^2}\right) \left(\frac{s^2}{kg \cdot m}\right)}

kg and s² cancel out, leaving
\sqrt{\frac{m^3}{m}}

which is
\sqrt{m^2}

or, more simply m