So the identity is actually:\sum_{i = 0}^{n-1} i = \frac{n(n-1)}{2}

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The identity \(\sum_{i = 0}^{n-1} i = \frac{n(n-1)}{2}\) is confirmed as correct in the discussion. Participants clarified that proper limits of summation must be applied to derive this formula accurately. The conversation emphasized the importance of understanding summation notation and its implications in mathematical proofs.

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killerfish
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Hi guys,

sry if i asked a silly qns. Is the below equivalent is true?

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No, that's not correct. Using your limits of summation you should have:

[tex]\sum_{i = 0}^{n-1} i = \frac{n(n-1)}{2}[/tex]
 

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