Solenoid Equation Help: Finding Current with Electron Motion

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SUMMARY

The discussion focuses on calculating the current (i) in a long solenoid with 100 turns/cm, through which an electron moves in a circular path of radius 2.30 cm at a speed of 0.04640c. The magnetic field (B) inside the solenoid is expressed as B = permeability constant * i * 100 turns/cm. The relationship between the force on the electron and its circular motion is established using the equations F = ma and qvB = m(v^2)/r, leading to the conclusion that the magnetic field produced by the solenoid is responsible for the electron's circular trajectory.

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  • Understanding of solenoid magnetic fields and their equations
  • Knowledge of circular motion dynamics and forces
  • Familiarity with the concept of electron motion in magnetic fields
  • Basic grasp of the permeability constant in electromagnetism
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  • Explore the relationship between current, magnetic field strength, and electron motion
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Homework Statement


A long solenoid has 100 turns/cm and carries current i. An electron moves within the solenoid in a circle of radius 2.30 cm perpendicular to the solenoid axis. The speed of the electron is 0.04640c (c= speed of light). Find the current i in the solenoid



B = permeability constant * i * 100turns/cm for the solenoid without the electron.


I guess I need the speed of the electron somewhere.

F = ma
qvB = m (v^2)/r
So we can get B of the circular loop.

What do I do next? I don't suppose we just equate these two B's.
 
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KoGs said:

Homework Statement


A long solenoid has 100 turns/cm and carries current i. An electron moves within the solenoid in a circle of radius 2.30 cm perpendicular to the solenoid axis. The speed of the electron is 0.04640c (c= speed of light). Find the current i in the solenoid



B = permeability constant * i * 100turns/cm for the solenoid without the electron.


I guess I need the speed of the electron somewhere.

F = ma
qvB = m (v^2)/r
So we can get B of the circular loop.

What do I do next? I don't suppose we just equate these two B's.

There's an idea. The only thing around producing a field to bend the path of that electron is the solenoid.
 

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