How Many Turns of Wire Are Needed for a Solenoid with These Specifications?

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    Homework Solenoid
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Homework Help Overview

The discussion revolves around calculating the number of turns of wire needed for a solenoid based on given specifications, including current, diameter, length, and magnetic field strength. The subject area is electromagnetism, specifically focusing on solenoids and magnetic fields.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using the formula B=n*u0*I to find the number of turns, with some questioning the application of the length in their calculations. There are attempts to clarify how to express the length and its impact on the results.

Discussion Status

The discussion includes various attempts to solve the problem, with one participant indicating they have arrived at a solution. However, there is no explicit consensus on the method used, and multiple interpretations of the calculations are present.

Contextual Notes

Participants mention different values for length in their calculations, indicating potential confusion about unit conversions or the correct application of the formula. There is a reference to needing to show work for clarity.

ahazen
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How many turns of wire would be on a solenoid carrying a current 4.9 A if the solenoid is 17 cm in diameter, 248 cm long, and the field at the center is 2.9 × 10-3 T?

I can't seem to get the right answer...

I plug the values into B=n*u0*I and then solve for N.
I know that n=N/length
 
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Hello ahazen,

What answer are you getting? (You need to show your work. :wink:)
 


I plug in: 2.9e-3=n(4*pi*10^-7)(4.9)
and then solve for n.
Then i divide by the length.

I keep getting something like 1899, 1.899, 18.99 depending on how i write the length (248, or .248, or .0248).
 


Thank you for your help:) I figured it out.:) I took B*L=N u0*I and solve for N to get 1168 turns.
 

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