Solenoid Induction Homework: Bz & Flux Calculation

Click For Summary

Homework Help Overview

The problem involves calculating the magnetic flux through a circular conducting loop placed inside a solenoid, with specific parameters for the solenoid and the loop. The solenoid has a varying current, and the loop is oriented at an angle to the solenoid's axis.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of magnetic flux and the influence of the number of turns in the loop on the flux. There is an exploration of the magnetic field's uniformity within the solenoid and its implications for the loop's area. Questions arise regarding the assumptions made about the solenoid's characteristics, particularly in approximating it as an infinite solenoid.

Discussion Status

Participants are actively engaging with the problem, questioning the relevance of the number of turns in the loop and clarifying concepts related to magnetic flux and field uniformity. Some guidance has been provided regarding the uniformity of the magnetic field within the solenoid, which seems to aid understanding.

Contextual Notes

The original poster expresses uncertainty about their calculations and the interpretation of the problem's hint regarding the approximation of the solenoid. There is a lack of consensus on the role of the number of turns in the loop affecting the flux calculation.

Bryon
Messages
98
Reaction score
0

Homework Statement


A solenoid has length L = 20 cm, radius 6 cm, and N1 = 4500 turns; its axis coincides with the z-axis. A circular conducting loop containing N2 = 11 turns of radius a = 1 cm is centered inside the solenoid; the plane of the loop makes a 30° angle with respect to the z-axis.

The current in the windings of the solenoid is varying with time according to the expression
I1(t) = 0.45 A + 0.14 (A/s) t.


Homework Equations



Biot-Savart(Center of a solenoid): Bz = u0nI
Magnetic flux: ϕ = ∫BdA= NBAcosϑ

The Attempt at a Solution



(a) Calculate the magnitude of the magnetic flux Φm through the loop at t = 3 s. (Absolute value)

I1(3s) = 0.45 A + 0.14 (A/s) (3s) = 0.87A

Bz = 4*pi*10^(-7)*(4500/0.2)*0.87 = 0.02459867 T

ϕ = (0.02459867 )*pi*(.01^2)*11*cos(30) = 7.3618137e-5 Tm^2

I did something wrong and I am not quite sure where. Any ideas?

I think i understand the concept. Since there is a small loop inside the solenoid at angle ϑ, I need to find the magnetic field at the center due to the current in the solenoid. Then I just have to find the total flux through the total area of the small circular loop that is sitting in the middle of the solenoid.

The question does provide a hint: Approximate this finite solenoid by an equivalent infinite solenoid to find the magnetic field in the central region.

Does this mean I can use a portion of the number of turns over a small distance to find the magnetic field?
 
Last edited:
Physics news on Phys.org
Need the picture?
 
Help?
 
Are you sure that the magnitude of the flux through the small loop depends upon the number of turns in that loop?
 
Hmmm. I am not entirely sure. The equation for magnetic flux calls for it, but I think that is for the solenoid itself.
 
I know that the magnetic field is uniform with in the solenoid near the center, and that would mean that the loop will see what ever its area is.
 
I think I just answered your question! Thanks it makes a lot more sense now.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 14 ·
Replies
14
Views
3K
Replies
4
Views
6K
Replies
3
Views
2K