Solid State Physics [Ashcroft] Chapter 1, Question 1a

In summary, the conversation discusses the probability of an electron suffering a collision in an infinitesimal time interval and how it relates to the probability of not having a collision for a given period of time. The participants suggest using a Poisson distribution to evaluate the probability and explain how it leads to the exponential function. The conversation also touches on solving problems from a book on Solid State Physics.
  • #1
FONE
4
0
Hi all,

Edit: Here's the question, in case you guys don't have the book:

In the Drude moel the probability of the electron suffering a collision in any infinintesimal interval dt is just dt/T.

a) show that an electron picked at random at a given moment had no collision during the preceding t seconds with the probability exp[-t/T]. Show that it will have no collision during the next t seconds with the same probability.


I'm trying to figure out how to get the exp[-t/T] part, 'cause nowhere in the chapter does it show a probability as XX exp[-t/T].

Please just help me get started. Any reference equations would be good...

Thanks!
 
Physics news on Phys.org
  • #2
Lets say our randomly picked electron was selected at time [itex]t_0[/itex], and we want to find the probability that this electron suffered no collisions from [itex]t=0[/itex] to [itex]t=t_0[/itex].
We know that the probability an electron to be scattered in an infintesimal interval [itex]dt[/itex] is

[tex]
P_{c}(t,t+dt) = \frac{dt}{\tau}.
[/itex]

Now the probability for the electron to suffer a collision, and the probability for it not to suffer a collision in this interval must sum to [itex]1[/itex]. So

[tex]
P_c(t,t+dt) + P_{nc}(t,+dt) = 1
[/tex]

Hence,
[tex]
P_{nc}(t,t+dt) = 1 - \frac{dt}{\tau}.
[/tex]

Now I will split the time interval [itex][0,t_0][/itex] into [itex]M[/itex] discrete intervals, such that

[tex]
t_0 = \sum_{n=1}^{M}dt = Mdt.
[/tex]

If I label the probability to not scatter in the interval [itex][0,ndt][/itex] as [itex]P_n[/itex], then I have

[tex]
P_1 = (1-\frac{dt}{\tau}),
[/tex]

and

[tex]
P_2 = P_1\times (1-\frac{dt}{\tau}) = (1-\frac{dt}{\tau})^2
[/tex]

The probability to not scatter from [itex]t=0[/itex] to [itex]t=Mdt=t_0[/itex] is

[tex]
P_M = \ldots
[/tex]

Once you have your expression for [itex]P_M[/itex], eliminate from this expression [itex]dt[/itex] using the definition of [itex]t_0[/itex], and notice that

[tex]
\lim_{dt\to 0} \equiv \lim_{M\to\infty}
[/tex]

Then you will have the limit of some function to evaluate...
 
Last edited:
  • #3
Hey,

Thanks for that! So if I divide up the t0 time into intervals, I can use the infinitesimal probability:

P(t, t+t0) = P(t, t+ndt) {n--> infinity}

so:
P(t, t+ndt) = (1-dt/T)^n, now we sub the definition of t0
P(t, t+t0) = (1 - t0/nT)^n, taking the lim n--> infinity
P(t, t+t0)=exp[-t0/T]

How do I distinguish between "before" and "after" t0 seconds? It looks like it's the same both ways, but how do I be rigorous about it?

Thanks!
 
  • #4
Just use the same logic as before. You have an expression for the particle not to have a collision from t=0 up to t=t_0 . Consider the probability for not scattering from t=0 to t=2t_0 (using the expression you derived). Express this in terms of the probability of not scattering from t=0 to t=t_0, and the probability not to scatter from t=t_0 to t=2t_0.
 
  • #5
Or you could use a Poisson distribution to evaluate the probability. Then you get the exponential function naturally from the poisson distribution.
 
  • #6
Ruy said:
jpr0

would you have the other problems of the I capitulate 1 and could it post for me?

Welcome to the PF, Ruy. We do not provide answers here on the PF, we provide tutorial help. If you have a specific problem that you need help on, please start a thread with the question, using the Homework Help template, and show us what work you've done so far.
 
  • #7
Somebody would have the subject 1c 1d 1e

1c)show as consequece of (a) ...
1d) show as consequence of (b) ...
1e) part (c0 implies that...
Thanks
 
  • #8
fes said:
Somebody would have the subject 1c 1d 1e

1c)show as consequece of (a) ...
1d) show as consequence of (b) ...
1e) part (c0 implies that...
Thanks

I'm not sure what you are asking. What is your question? It is probably best for you to start a new thread here in the Homework Help forums, use the Homework Help question template that is provided, and show your work so far so that we can help you in a tutorial way.
 
  • #9
Hi every body, I am new comer and be interested in Solid State Physics [Ashcroft]. Has anyone have solution for the book. chapter 9, Problem 2(Density of levels...)?
I am confused by intergarating delta function with separated variable as shown in.
thank you
 
  • #10
Repetit said:
Or you could use a Poisson distribution to evaluate the probability. Then you get the exponential function naturally from the poisson distribution.

Welcome to the PF, Repetit. You should start a new thread with your question. Be sure to use the Homework Help Template that you are given when starting new homework question threads, and fill out the sections on the Relevant Equations and show your Attempt at a Solution.

We certainly don't do your schoowork problems for you, but we can usually offer tutorial hints that will help you to do the work yourself.
 

1. What is solid state physics?

Solid state physics is the study of the physical properties and behavior of solid materials, such as crystals, semiconductors, and metals. It involves understanding the structure, properties, and interactions of atoms and molecules in solids.

2. Who is the author of "Solid State Physics"?

The author of "Solid State Physics" is Neil W. Ashcroft, a British-American physicist and professor of physics at Cornell University.

3. What is the main focus of Chapter 1 in "Solid State Physics" by Ashcroft?

The main focus of Chapter 1 in "Solid State Physics" is to introduce the basic concepts and principles of solid state physics, including the structure of solids, crystal symmetries, and lattice vibrations.

4. What is the significance of studying solid state physics?

Studying solid state physics is important for understanding the fundamental properties and behavior of materials, which has numerous practical applications in fields such as electronics, materials science, and engineering.

5. What background knowledge is necessary to understand "Solid State Physics" by Ashcroft?

A basic understanding of classical mechanics, electromagnetism, and quantum mechanics is necessary to understand "Solid State Physics" by Ashcroft. Familiarity with basic mathematical concepts such as vectors, matrices, and differential equations is also helpful.

Similar threads

  • Advanced Physics Homework Help
Replies
1
Views
807
Replies
1
Views
2K
  • Atomic and Condensed Matter
Replies
6
Views
1K
  • Atomic and Condensed Matter
Replies
11
Views
2K
  • Science and Math Textbooks
Replies
7
Views
3K
  • Advanced Physics Homework Help
Replies
1
Views
5K
  • Advanced Physics Homework Help
Replies
1
Views
3K
  • Advanced Physics Homework Help
Replies
1
Views
11K
  • Advanced Physics Homework Help
Replies
1
Views
3K
  • Advanced Physics Homework Help
Replies
1
Views
1K
Back
Top