Solubility Constant vs Aqueous solubility

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Discussion Overview

The discussion revolves around the calculation of the aqueous solubility of AgBr based on its solubility constant (Ksp). Participants explore methods for determining the solubility, including the use of an ICE table and direct calculations from the Ksp value.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant states the solubility constant for AgBr in water is 5.2 x 10-13 and seeks to find its aqueous solubility.
  • Another participant suggests calculating the concentration of Ag+ in the saturated solution, noting that [Ag+] = [Br-].
  • A later reply confirms the calculation of x as 7.2 x 10-7 based on the equation 5.2 x 10-13 = x2.
  • Participants discuss the use of the ICE table, with one indicating it is not necessary for this problem, while another agrees that it can be saved for more complex scenarios.

Areas of Agreement / Disagreement

Participants generally agree on the method of calculating the solubility but express differing opinions on the necessity of using an ICE table for this specific problem.

Contextual Notes

Some assumptions about the conditions under which the solubility constant applies may not be explicitly stated, and the discussion does not resolve the appropriateness of using the ICE table in this context.

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Homework Statement



The solubility constant for AgBr in water is 5.2 x 10-13. What is the aqueous solubility of AgBr?

Homework Equations



Ksp= [Ag+][Br-]

AgBr is a constant and therefore is not part of the Ksp.

The Attempt at a Solution



NVM solved problem. Should use ICE table.
 
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Just calculate concentration of Ag+ in the saturated solution - remembering that [Ag+] = [Br-] - and you are done. That's not much different from using ICE table, but ICE table as such is an overkill here.

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methods
 
Thanks for the help borek. It should be 5.2 x 10-13= x^2.

x= 7.2 x 10^-7
 
Exactly.

It doesn't differ from what you should get using ICE table, so it is not an error to use it, just no need for elaborate approach. Save it for difficult problems :wink:

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methods
 

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