(This actually came up in a homework assignment). My teacher dismissed it as d.n.e. but I actually believe it has the solution set of 'all real numbers'; it has pertinence to a specific problem in calc III that I find interesting. I have read some contradictory statements on the web.
The Attempt at a Solution
I'm thinking of division as 'how many times a denominator can go into a numerator':
e.g. 8/2 = 4 because 2 goes into 8 four times.
Following this logic, how many times can zero go into zero? one,two, three... how ever many times you want. Therefore 0/0 has the solution set of 'all real numbers'.
Is there an error in my logic?