Solve 1st Order ODE: x^2+y^2+2xy+y^2+(x^3/3)dy/dx=0

  • Thread starter Thread starter ngj
  • Start date Start date
  • Tags Tags
    First order Ode
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 1K views
ngj
Messages
1
Reaction score
0
i have this differential equation of the first order
[x^2+y^2]+[2xy+y^2+(x^3/3)]dy/dx=0
i tried to solve it by substitution putting x^2+y^2=v ,but it doesn't work also it is not exact or homogeneus to solve it by these methods. I still believe it can be solved using substitution but i can't reach to the correct one
so please help me solving this diff. equation
 
Physics news on Phys.org
ngj said:
i have this differential equation of the first order
[x^2+y^2]+[2xy+y^2+(x^3/3)]dy/dx=0
i tried to solve it by substitution putting x^2+y^2=v ,but it doesn't work also it is not exact or homogeneus to solve it by these methods. I still believe it can be solved using substitution but i can't reach to the correct one
so please help me solving this diff. equation
You might try u = y/x ==> y = ux, so y' = u + u'x.

I can't guarantee it will work, but it's worth a try if you can get the DE to separate.